How Is Acceleration Calculated in Uniform Acceleration Problems?

In summary, uniform acceleration is the constant change in an object's velocity over time. It is calculated by dividing the change in velocity by the change in time. The key difference between constant and uniform acceleration is that constant acceleration remains the same throughout the motion, while uniform acceleration refers to a constant change in velocity. Uniform acceleration is related to Newton's Second Law of Motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Real-life examples of uniform acceleration include free falling objects, objects rolling down a ramp, and cars accelerating at a constant rate on a straight road.
  • #1
TCleland
2
0

Homework Statement



A drag car starting from rest and accelerating uniformly acquires a speed of 60 m/s while traveling a distance of 270m. Calculate the acceleration.

Homework Equations



No idea

The Attempt at a Solution



No idea
 
Physics news on Phys.org
  • #2
There is a very basic kinematic equation that relates everything in this problem together. Have another review of this section in your textbook.
 
  • #3
No textbook and no notes.

He just wanted us to answer this. Help anyone?
 
  • #5


I am happy to assist you with this problem. The equations that can be used to solve uniform acceleration problems are:

1. v = u + at (where v is final velocity, u is initial velocity, a is acceleration, and t is time)

2. s = ut + 1/2 at^2 (where s is distance, u is initial velocity, a is acceleration, and t is time)

Using the given information, we can rearrange equation 2 to solve for acceleration:

a = 2(s - ut) / t^2

Substituting the given values of s = 270m, u = 0 m/s, and t = unknown, we can solve for t:

60 m/s = 0 m/s + a(t)
60 m/s = at
t = 60 m/s / a

Substituting t = 60 m/s / a into the equation for acceleration, we get:

a = 2(270m - 0 m/s * 60 m/s / a) / (60 m/s / a)^2
a = 2(270m) / 3600 m^2/s^2
a = 0.15 m/s^2

Therefore, the acceleration of the drag car is 0.15 m/s^2. I hope this helps you understand how to solve uniform acceleration problems. Remember to always use the appropriate equations and units when solving problems in physics.
 

Related to How Is Acceleration Calculated in Uniform Acceleration Problems?

1. What is uniform acceleration?

Uniform acceleration is the constant rate at which an object's velocity changes over time. In other words, the object's speed increases or decreases by the same amount every second.

2. How is uniform acceleration calculated?

Uniform acceleration is calculated by dividing the change in velocity by the change in time. This is represented by the equation a = (vf - vi)/t, where a is the acceleration, vf is the final velocity, vi is the initial velocity, and t is the time interval.

3. What is the difference between constant and uniform acceleration?

Constant acceleration refers to a situation where the acceleration remains the same throughout the entire motion, while uniform acceleration specifically refers to a constant change in velocity over time.

4. How does uniform acceleration relate to Newton's Second Law of Motion?

Newton's Second Law of Motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. In the case of uniform acceleration, this means that the net force acting on the object is constant.

5. What are some real-life examples of uniform acceleration?

Some real-life examples of uniform acceleration include free falling objects, objects rolling down a ramp, and cars accelerating at a constant rate on a straight road.

Similar threads

  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
987
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
8
Views
346
  • Introductory Physics Homework Help
Replies
6
Views
878
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
2K
  • Introductory Physics Homework Help
Replies
6
Views
545
Replies
7
Views
3K
  • Introductory Physics Homework Help
Replies
5
Views
1K
Back
Top