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MMCS
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A mine cage of mass 4 tonne is to be raised with an acceleration of 1.5m/s^2
using a hoist drum of 1.5m diameter. The drum’s mass is 750kg and its radius of gyration is 600mm.The effect of bearing friction is equivalent to a torque of 3kNm at the hoist drum. What isthe driving torque required on the drum ? If the driving torque ceases when the load is
moving upwards at 6m/s, find the deceleration of the load and how far it travels before
coming to rest.
My question is the second part, to find the deceleration.
i already know the answer to the first part, which is the torqure required, which is 37440Nm
I get F = M*A >> A = F/M >>> 37440/4000 = 9.36m/s^2
but i have the answer to be 9.64m/s^2
using a hoist drum of 1.5m diameter. The drum’s mass is 750kg and its radius of gyration is 600mm.The effect of bearing friction is equivalent to a torque of 3kNm at the hoist drum. What isthe driving torque required on the drum ? If the driving torque ceases when the load is
moving upwards at 6m/s, find the deceleration of the load and how far it travels before
coming to rest.
My question is the second part, to find the deceleration.
i already know the answer to the first part, which is the torqure required, which is 37440Nm
I get F = M*A >> A = F/M >>> 37440/4000 = 9.36m/s^2
but i have the answer to be 9.64m/s^2