- #1
Sekonda
- 207
- 0
Hey guys, here is the question :
A 5.4kg toboggan carrying 35kg of sand slides from rest down an icy 90m slope inclined
at 30◦ below the horizontal. The sand leaks from the back of the toboggan at a rate of
2.3kgs−1. How long does it take the toboggan to reach the bottom of the slope?
I found that the mass of the system at anyone time can be written as a simple linear relationship and so the weight of the system down the slope at any time 't' can also be expressed using this same relationship.
Using this to determine the acceleration down the slope at any time 't', I found that the acceleration is constant at 0.5g down the slope.
Using the SUVAT equations I then determined the time taken to be approximately 6.061s.
Is this correct? Or am I being an idiot somewhere :P
Thanks for any comments/help
Cheers!
A 5.4kg toboggan carrying 35kg of sand slides from rest down an icy 90m slope inclined
at 30◦ below the horizontal. The sand leaks from the back of the toboggan at a rate of
2.3kgs−1. How long does it take the toboggan to reach the bottom of the slope?
I found that the mass of the system at anyone time can be written as a simple linear relationship and so the weight of the system down the slope at any time 't' can also be expressed using this same relationship.
Using this to determine the acceleration down the slope at any time 't', I found that the acceleration is constant at 0.5g down the slope.
Using the SUVAT equations I then determined the time taken to be approximately 6.061s.
Is this correct? Or am I being an idiot somewhere :P
Thanks for any comments/help
Cheers!