NRip897 said:Homework Statement
A 0.39 kg mass falls from a height of 2.9 m. If all of the energy of this mass could be converted to visible light of wavelength 5.5 × 10^−7 m, how many photons would be produced? The acceleration of gravity is 9.8 m/s^2 . Planck’s constant is 6.63 × 10^−34 J · s, and the speed of light is 3 × 10^8 m/s.
Homework Equations
E=hc/λ
p=h/λ
x=.5at^2
The Attempt at a Solution
E=hc/λ=(1.99x10^-25)/(5.5x10^-7)=3.618x10^-10J
x=.5at^2 > 2.9=.5(9.8)t^2 > t=.769s
Quantum energy levels refer to the specific, discrete energy values that an electron can occupy within an atom. These values are determined by the electron's distance from the nucleus and can be visualized as different energy levels or "shells" around the nucleus.
When an electron transitions from one energy level to another, it either absorbs or emits a specific amount of energy in the form of a photon. This energy change is what causes the unique spectral lines seen in atomic spectra.
No, according to the principles of quantum mechanics, an electron cannot exist between energy levels. It can only exist in a specific energy state and can only transition between levels by absorbing or emitting a specific amount of energy.
The number and arrangement of an atom's energy levels determine its chemical properties. The energy levels dictate the distance of the outermost electrons from the nucleus, which in turn affects the atom's reactivity and ability to form chemical bonds.
While quantum energy levels cannot be directly observed, their effects can be seen through experiments such as atomic emission or absorption spectroscopy. These techniques allow scientists to study the energy levels of atoms by analyzing the wavelengths of light emitted or absorbed by the atoms.