How to calculate Aphelion distance?

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  • #1
Mikael17
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Is it possible to calculate the Aphelion distance, - when I only know the Perihelion distance and perihelion speed ?
 
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  • #2
Mikael17 said:
Is it possible to calculate the Aphelion distance, - when I only know the Perihelion distance and perihelion speed ?
What is your question?
In the main text the question is "Is it possible?". The answer of that question is a three-letter word. "Yes"
In the headline, the question is "How". This takes a bit longer equation.
Now, note that for each apside, the speed is tangential - the radial component of speed is zero at apsides.
The total energy of a body is E=m(v2/2)-m(GM/r). The angular momentum at an apside is L=m(vr).
Therefore, given r1, v1 and GM (m cancels out), you can calculate
E/m=v12/2-GM/r1
L/m=v1r1

This is two equations for two unknowns. Could be solved. Given one pair of v and r, which are a solution, find the pair of v and r which are the other solution.
 
  • #3
I don't see how you can do it without the mass of the primary (the ##M## in post #2).
 
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  • #4
Ibix said:
I don't see how you can do it without the mass of the primary (the ##M## in post #2).
Very much this. However, given the mass of the primary and (indirectly) the angular momentum the full effective potential is known as well as thd classical turning point. It is then just a matter of finding the other classical turning point, which amounts to finding the roots of a second degree polynomial.
 
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  • #5
Ibix said:
I don't see how you can do it without the mass of the primary (the ##M## in post #2).
If the OP was asking a well-defined question one could assume that "perihelion" and "aphelion" is a reference to the Sun as primary mass.
 
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  • #6
Mikael17 said:
Is it possible to calculate the Aphelion distance, - when I only know the Perihelion distance and perihelion speed ?
If you know the primary mass (e.g. Sun) then yes. It follows more or less directly from the vis-viva equation that holds for all two-body keplerian orbits.
 
  • #7
When you know the distance and speed at one apse, and GM, you may find apoapse distance. But this is only one possibility. You may instead find out that there is only one apside (the given apside that was a periapse); or that the given apside was the apoapside; or that there is no apside line.
 
  • #8
snorkack said:
When you know the distance and speed at one apse, and GM, you may find apoapse distance. But this is only one possibility. You may instead find out that there is only one apside (the given apside that was a periapse); or that the given apside was the apoapside; or that there is no apside line.
Indeed. Using vis-viva and solving for one apsis distance gives a direct "symmetric" relationship of this distance as a function of the other apsis distance and speed. This distance is then either positive, infinite or negative for elliptic, parabolic or hyperbolic orbits, respectively, so one equation covers all cases.
 
  • #9
Filip Larsen said:
Using vis-viva and solving for one apsis distance gives a direct "symmetric" relationship of this distance as a function of the other apsis distance and speed. This distance is then either positive, infinite or negative for elliptic, parabolic or hyperbolic orbits, respectively, so one equation covers all cases.
The case of positive distance further divides into the cases where the found apsis distance was bigger than given apsis distance (found was apoapsis), found apsis distance was equal to given apsis distance (neither was apsis after all because the orbit was not elliptic) or the found apsis distance was smaller than given apsis distance (found apsis was periapsis).
 
  • #10
snorkack said:
The case of positive distance further divides into the cases where the found apsis distance was bigger than given apsis distance (found was apoapsis), found apsis distance was equal to given apsis distance (neither was apsis after all because the orbit was not elliptic) or the found apsis distance was smaller than given apsis distance (found apsis was periapsis).
Yes, but my point is that since you end up with an equation that is valid for all cases you don't really need to "worry" about the orbit classification unless you specifically want to know or verify that too. Also, the full orbit classification is more of a mathematical thing since in practice there are only either elliptical or hyperbolic orbits with the rest being "degenerate" (i.e. only approximately true) cases.
 
  • #11
One caveat that's probably worth mentioning is that these approaches are assuming that the satellite has negligible mass in comparison to the primary. Depending on how precise you need to be, "negligible" could mean anything up to planetary masses if the primary is indeed the Sun.

The maths is actually no worse if the satellite mass is non-negligible, but you do need to know the satellite mass and you do need to take care about how you defined perihelion distance. You want to use the satellite-to-barycenter distance, and this will be significantly different from the satellite-to-primary distance in this case.
 
  • #12
Ibix said:
One caveat that's probably worth mentioning is that these approaches are assuming that the satellite has negligible mass in comparison to the primary. Depending on how precise you need to be, "negligible" could mean anything up to planetary masses if the primary is indeed the Sun.

The maths is actually no worse if the satellite mass is non-negligible, but you do need to know the satellite mass and you do need to take care about how you defined perihelion distance. You want to use the satellite-to-barycenter distance, and this will be significantly different from the satellite-to-primary distance in this case.
To elaborate on this with the teeniest amount of math. The two-body problem with a Kepler potential separates into the motion of the barycenter (free motion so rectilinear) and a Kepler potential problem for the separation vector of the masses with gravitational potential ##- GM/r## with ##M = m_1 + m_2## being the total mass of the system (the potential energy is obviously ##- Gm_1m_2/r##, but the mass entering in the kinetic energy for the problem for the separation vector is the reduced mass ##m_1 m_2/M##).

The separation from the barycenter of mass ##m_2## is a factor ##m_1/M## of the separation of the masses (just by definition of the barycenter) if you prefer looking at the apsides of that rather than the apsides of the two-body separation.

If you are interested in the separation apsides rather than the mass-barycenter apsides, everything is just as above with the primary mass replaced by the total mass.
 
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  • #13
Filip Larsen said:
If the OP was asking a well-defined question one could assume that "perihelion" and "aphelion" is a reference to the Sun as primary mass.

Helios (Greek for sun) is an easy one and 'Gee' (a greek term for Earth) is also familiar but there are some others like
Starperiastron, apoastron-astrons
This link shows more. but it's far from universal.

I'd like a general term for apo and peri points of an orbit.
 
  • #15
Orodruin said:
What is wrong with the one we have?
Oh for a content addressable memory. Thanks! I promise to use it whenever possible .
 

What is the aphelion distance?

The aphelion distance is the point in the orbit of a planet, asteroid, or comet at which it is furthest from the Sun. Each object orbiting the Sun, including Earth, follows an elliptical path, making the aphelion the farthest point from the Sun during the orbit.

How can you calculate the aphelion distance of a planet?

To calculate the aphelion distance of a planet, you can use the formula: Aphelion = a(1 + e), where 'a' is the semi-major axis of the orbit and 'e' is the eccentricity of the orbit. Both of these values are typically known and can often be found in astronomical databases or scientific literature.

What is the semi-major axis and how do you find it?

The semi-major axis is half of the longest diameter of an elliptical orbit. It represents the average distance from the center of the orbit (and the Sun in the case of solar orbits) to any point on the orbit's perimeter. The value of the semi-major axis can be found in astronomical data for the object in question, as it is a standard measurement used to describe orbits.

What is orbital eccentricity and how is it determined?

Orbital eccentricity measures how much an orbit deviates from being circular. An eccentricity of 0 indicates a perfect circle, while values approaching 1 indicate increasingly elongated ellipses. Eccentricity can be calculated based on observations of an object's speed and distance at various points in its orbit, or it can be derived from theoretical models of the object's motion.

Why does the aphelion distance matter in astronomy?

The aphelion distance is crucial for understanding the dynamics of solar system objects. It affects the amount of solar radiation the object receives at different times in its orbit, which can influence atmospheric conditions, surface temperatures, and overall climate if the object is a planet. Additionally, knowing the aphelion and perihelion (closest approach to the Sun) helps astronomers calculate the orbital energy and stability of the orbit over time.

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