How to Calculate Heat Loss Per Hour Through a Glass Window Pane?

In summary, the task is to calculate the amount of heat lost through a 2.7 m high, 2.4 m wide, and 2 mm thick glass window pane with a temperature difference of 4°C between its inner and outer surfaces. The equation to solve this involves a constant, k, which can represent either thermal conduction or thermal resistance depending on the given units. The power lost is expected to increase with the area of the window and the temperature difference, following the equation P = k A dt.
  • #1
preluderacer
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0

Homework Statement



A glass window pane is 2.7 m high, 2.4 m wide and 2 mm thick. The temperature at the inner surface of the glass is and at the outer surface 4°C. How much heat is lost each hour through the window?



The Attempt at a Solution



I have the stats on the glass like specific heat ect.

Im not quite sure what equations to use to solve this
 
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  • #2
How would you expect the power lost to depend on the area of the window and the temperature difference?

Do you know the equation for electrical resistance of a material? How is this similar?
 
  • #3
no, I am not quite sure what that equation is.
 
  • #4
You can work it out simply.

You expect the heat loss to go up with more area - double the area = double the heat loss.
And you expect it be proportional to the temperature difference, double the temperature difference double the heat loss.

so you have power is proprtional to area * temperature differences
or P = k A dt
where k is some constant for your material

Depending on how your data is given 'k' might be thermal conduction = bigger number is more heat lost, or thermal resistance = small number is more heat lost, so you migth have K or 1/K in the equation. You can tell from the units given for 'k'
 
  • #5
problem, but I can provide some guidance. To determine the heat loss per hour, you will need to calculate the thermal conductivity of the glass window pane. This can be done by using the formula k = (Q/t)(L/A)(1/ΔT), where k is the thermal conductivity, Q/t is the heat flow rate, L is the thickness of the glass, A is the area of the window pane, and ΔT is the temperature difference between the inner and outer surfaces.

Once you have calculated the thermal conductivity, you can then use the formula Q = kAΔT/t to determine the amount of heat lost per hour. Here, Q represents the heat loss per hour, k is the thermal conductivity, A is the area of the window pane, ΔT is the temperature difference, and t is the time in hours.

Remember to convert all units to the appropriate SI units (meters for length, square meters for area, seconds for time) before plugging them into the equations. I hope this helps guide you in solving the problem. Good luck!
 

1. How is heat loss per hour calculated?

The calculation for heat loss per hour depends on several factors such as the material of the object, its surface area, and the temperature difference between the object and its surroundings. The most common formula used is Q = U x A x ΔT, where Q is the heat loss per hour, U is the overall heat transfer coefficient, A is the surface area, and ΔT is the temperature difference.

2. What is considered a high amount of heat loss per hour?

The amount of heat loss per hour can vary depending on the context. However, in general, a high amount of heat loss per hour is considered anything above 100 watts. This can be a significant amount of energy loss and can lead to higher energy bills and a less comfortable environment.

3. How does insulation affect heat loss per hour?

Insulation plays a crucial role in reducing heat loss per hour. It acts as a barrier between the object and its surroundings, minimizing the temperature difference and reducing the amount of heat that can escape. The better the insulation, the lower the heat loss per hour will be.

4. Can heat loss per hour be prevented?

While it is not possible to completely eliminate heat loss per hour, it can be significantly reduced through proper insulation, sealing air leaks, and using energy-efficient materials. Regular maintenance and upgrades can also help prevent excessive heat loss per hour.

5. Why is it important to know the amount of heat loss per hour?

Knowing the amount of heat loss per hour is crucial for energy conservation and cost savings. It allows us to identify areas where energy is being wasted and take steps to reduce heat loss. It also helps us understand the efficiency of our heating systems and make informed decisions about energy usage.

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