How to Calculate the Velocity of a Projected Object at Impact?

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In summary, the student found that the velocity of the sack as it hits the ground is 24.5 m/s. The student used the equations for velocity to solve for the final answer of 24.5 m/s.
  • #1
ashi1416
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Homework Statement


a physics student pitches a sack of doorknobs into the air with an initial velocity of 24.5 m/s at 36.9degrees from the horizontal.
i know the:
time=3.0s
horizontal distance traveled=58.8m
time when sack is at max height=1.5s
max height sack reaches=11.03m

but i need to know how to figure:
the velocity of the sack as it hits the ground=?

ok so i have the correct answer its:
24.5 m/s, trajectory is 322.9degrees or 36.9degrees with horizontal


Homework Equations



i need to know how you got this answer
like what equations did you use?

The Attempt at a Solution



i got that far as to figuring out all the questions but how do you get that one?


(my teacher gives us the question and the answer and wants to see our work...thats how i know that last answer)
 
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  • #2
ashi1416 said:

Homework Statement


a physics student pitches a sack of doorknobs into the air with an initial velocity of 24.5 m/s at 36.9degrees from the horizontal.
i know the:
time=3.0s
horizontal distance traveled=58.8m
time when sack is at max height=1.5s
max height sack reaches=11.03m

but i need to know how to figure:
the velocity of the sack as it hits the ground=?

ok so i have the correct answer its:
24.5 m/s, trajectory is 322.9degrees or 36.9degrees with horizontal

Homework Equations



i need to know how you got this answer
like what equations did you use?

The Attempt at a Solution



i got that far as to figuring out all the questions but how do you get that one?(my teacher gives us the question and the answer and wants to see our work...thats how i know that last answer)

What are the x and y components of velocity when the sack lands?

[tex]\vec{V} = \vec{V_x} +\vec{V_y}[/tex]
 
  • #3
x=58.8 and y=0
is that what your asking for??
 
  • #4
noo
ok but how do you get the Vx and Vy
the Vo=24.5
 
  • #5
ashi1416 said:
x=58.8 and y=0
is that what your asking for??

What was it horizontal velocity at that time + what was the vertical velocity.

Add them together as vectors. You will get a magnitude and an angle.
 
  • #6
ashi1416 said:
noo
ok but how do you get the Vx and Vy
the Vo=24.5

You had to have had the horizontal velocity to know how far it traveled.
 
  • #7
Vy is given by how fast it was going falling from 11 meters.

Or Vy = g*t to fall from that height where t is the same t you found to get to that height.
 
  • #8
oh ok i have the initial horizontal velocity its 19.59 and the initial vertical velocity is 14.7

do need any final velocitys to solve this?
or am i going off the initial the whole time?
 
  • #9
ashi1416 said:
oh ok i have the initial horizontal velocity its 19.59 and the initial vertical velocity is 14.7

do need any final velocitys to solve this?
or am i going off the initial the whole time?

The initial Vx will remain the same.

The final Vy will be downward. Since it was at the same height at the end that it started, downward velocity will be the same magnitude as the start, but opposite sign. But note it's only because it's at the same height.
 
  • #10
oh ok.

ok so what like equatitions with the numbers in them would you use to got to the final answer of 24.5m/s?
 
  • #11
ashi1416 said:
oh ok.

ok so what like equatitions with the numbers in them would you use to got to the final answer of 24.5m/s?

The components form two sides of a right triangle. Any way you can think of to calculate the Hippopotamus?
 

Related to How to Calculate the Velocity of a Projected Object at Impact?

What is the concept of launching at angles?

Launching at angles is the act of propelling an object at an angle rather than straight ahead. This can be achieved by altering the direction of the object's initial velocity.

Why is launching at angles important in science?

Launching at angles is important in science because it allows for the study of projectile motion, which is the motion of objects that are launched at an angle and experience the effects of gravity. This concept is essential for understanding various phenomena, such as the trajectory of a rocket or the path of a baseball.

What factors affect the trajectory of a launched object?

The trajectory of a launched object is affected by several factors, including the initial velocity, the angle of launch, the air resistance, and the gravitational force. These factors can be manipulated to alter the path of the launched object.

How does the angle of launch affect the range of a projectile?

The angle of launch directly affects the range of a projectile. The optimal angle for maximum range is 45 degrees, as this angle allows for the highest combination of horizontal and vertical velocity. Launching at angles higher or lower than 45 degrees will result in a shorter range.

What are some real-life applications of launching at angles?

Launching at angles has various real-life applications, such as in sports, where throwing or hitting an object at different angles can affect its trajectory. It is also crucial in fields such as engineering and military, where the launch of missiles and other projectiles must be carefully calculated for maximum precision and efficiency.

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