- #1
svletana
- 21
- 1
I was doing the calculations for this: http://fermi.la.asu.edu/PHY531/cylinder/index.html
But I can't figure out how to go from [itex]\frac{d\sigma}{d\phi}[/itex] to the total cross section. My guess was that you did the integral from [itex]\phi=0[/itex] to [itex]\phi=2\pi[/itex], but that's not helping since I can't tell either how they got the absolute value squared inside the sum..
Thanks for anyone who listens :)
But I can't figure out how to go from [itex]\frac{d\sigma}{d\phi}[/itex] to the total cross section. My guess was that you did the integral from [itex]\phi=0[/itex] to [itex]\phi=2\pi[/itex], but that's not helping since I can't tell either how they got the absolute value squared inside the sum..
Thanks for anyone who listens :)