Please post the problem as stated to you.mattz205 said:Homework Statement
How would i go about finding the electric field and potential difference when there is a constant charge density between the capacitor rather than a vacuum?
Homework Equations
int E dot dA = Qencl/epsilon0
V ab = int E dot dl
The Attempt at a Solution
to be honest I am not really sure where to start this, i know how to find all this when there is a vacuum or dielectric, but what would i do to find it when there is a constant charge density?
Potential difference, also known as voltage, is the difference in electric potential between two points in an electric circuit. It is measured in volts (V).
The potential difference can be calculated by dividing the amount of charge (Q) by the capacitance (C) of the circuit. This can be represented by the equation V = Q/C.
Constant charge refers to the amount of electric charge that remains unchanged or constant in a given system. This means that there is no net flow of charge in or out of the system.
Yes, potential difference can be negative. This indicates that the flow of electric charge is in the opposite direction of the conventional current flow. It is important to pay attention to the direction of the current when calculating potential difference.
Potential difference is directly related to electric potential energy. An increase in potential difference results in an increase in potential energy, while a decrease in potential difference results in a decrease in potential energy. This relationship is represented by the equation PE = QV, where PE is the electric potential energy, Q is the amount of charge, and V is the potential difference.