You forgot to consider Tarzans weight.Jade_lowe said:Homework Statement:: Tarzan plans to cross a gorge by swinging in an arc from a hanging vine. if his arms are capable of exerting a force of 1500 N on the vine, what is the maximum speed he can tolerate at the lowest point of his swing? His mass is 80 kg, and the vine is 4.5 m long.
Relevant Equations:: Fmax= mvmax^2/r
T= m*vmax^2/r 1500 = (80kg)vmax^2/4.5
No. It isn’t. Do a free body diagram of Tarzan at the base of the swing.Jade_lowe said:The mass is his weight.
We’ll, they should have stated local ##g## too, but you can assume 9.81 m/s².Jade_lowe said:This is what the question gave me.
Welcome, @Jade_lowe !Jade_lowe said:The mass is his weight.
To calculate Vmax squared for circular motion, you can use the formula Vmax^2 = r * ω^2, where r is the radius of the circle and ω is the angular velocity. This formula is derived from the equation for centripetal acceleration, a = r * ω^2.
Vmax squared represents the maximum velocity that an object can achieve in circular motion. It is important because it helps us understand the speed and acceleration of objects moving in circular paths.
No, Vmax squared cannot be negative in circular motion. This is because velocity and speed are always positive quantities, and squaring a negative number will result in a positive number.
In circular motion, Vmax squared is directly proportional to the radius of the circle. This means that as the radius increases, so does Vmax squared. This relationship is described by the formula Vmax^2 = r * ω^2.
No, Vmax squared and tangential velocity are not the same. Vmax squared represents the maximum velocity an object can achieve in circular motion, while tangential velocity is the instantaneous velocity of an object at a specific point on its circular path.