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bmac88
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Homework Statement
Hey, if a 1000 kg car is moving at 10 m/s brakes to stop in 5 seconds. What would the avergae breaking force be?
The force required to stop a car is dependent on its mass, speed, and the time it takes to stop. In this scenario, the car has a mass of 1000 kg, is moving at a speed of 10 m/s, and takes 5 seconds to stop. Using the formula F = ma (force = mass x acceleration), we can calculate the force required to stop the car to be 2000 N.
The safety of a car stopping in 5 seconds depends on various factors such as the road conditions, speed limit, and driver reaction time. In general, 5 seconds is considered a safe amount of time for a car to come to a complete stop. However, it is always important for drivers to maintain a safe distance from other vehicles and be prepared to stop in case of any unexpected situations.
The distance a car will travel before coming to a stop is determined by its initial velocity, final velocity, and the time it takes to stop. In this scenario, the car is traveling at a speed of 10 m/s and comes to a stop in 5 seconds, so it will travel a distance of 50 meters before stopping. This can be calculated using the formula d = vi*t + 1/2at^2 (distance = initial velocity x time + 1/2 x acceleration x time squared).
The acceleration of a car during braking can be calculated using the formula a = (vf - vi)/t (acceleration = change in velocity/time). In this scenario, the initial velocity (vi) is 10 m/s, the final velocity (vf) is 0 m/s, and the time (t) is 5 seconds. Plugging these values into the formula, we get an acceleration of -2 m/s^2. This indicates that the car is decelerating at a rate of 2 m/s^2.
The weight of a car does have an impact on its braking distance. A heavier car will take longer to come to a stop compared to a lighter car. This is because it requires more force to slow down and stop a heavier car. Therefore, the braking distance for a 1000 kg car will be longer than that of a 500 kg car, assuming all other factors are the same.