MHB Inserting Nodes After Q: Let's Double Check!

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To insert a node pointed to by P after a node pointed to by Q, simultaneous assignment notation is used, indicated by the symbol $\leftarrow$. This means that the assignments occur at the same time, making the order of operations irrelevant in this context. However, when implementing the algorithm in a programming language like C, it is important to first update Q->next->prev before changing Q->next. This distinction is crucial for correct implementation in code versus theoretical algorithm notation. Understanding this difference clarifies the insertion process in linked list operations.
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Hi! (Smirk)

According to my notes, if we want to insert a node pointed to by P just after node poited to by Q, we have to do the following changements:

$$\begin{pmatrix}
P->prev\\
P->next\\
Q->next\\
Q->next->prev
\end{pmatrix} \leftarrow
\begin{pmatrix}
Q\\
Q->next\\
P\\
P
\end{pmatrix}$$

Shouldn't it be $\rightarrow$ ? :confused:

Also, shouldn't we first change [m]Q->next->prev[/m] and then [m]Q->next[/m]?

Or am I wrong? (Worried)
 
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evinda said:
Hi! (Smirk)

According to my notes, if we want to insert a node pointed to by P just after node poited to by Q, we have to do the following changements:

$$\begin{pmatrix}
P->prev\\
P->next\\
Q->next\\
Q->next->prev
\end{pmatrix} \leftarrow
\begin{pmatrix}
Q\\
Q->next\\
P\\
P
\end{pmatrix}$$

Shouldn't it be $\rightarrow$ ? :confused:

Also, shouldn't we first change [m]Q->next->prev[/m] and then [m]Q->next[/m]?

Or am I wrong? (Worried)

Hey! (Wave)

The symbol $\leftarrow$ means simultaneous assignment.
It means that we do for instance: [m]P->prev = Q;[/m]. (Smirk)

Since the assignment is simultaneous, the order is not relevant.
You may interpret it as if the right hand values are first copied to 4 temporary variables, and then those 4 temporary variables are copied to the left hand variables. (Nerd)
 
I like Serena said:
Hey! (Wave)

The symbol $\leftarrow$ means simultaneous assignment.
It means that we do for instance: [m]P->prev = Q;[/m]. (Smirk)

Since the assignment is simultaneous, the order is not relevant.
You may interpret it as if the right hand values are first copied to 4 temporary variables, and then those 4 temporary variables are copied to the left hand variables. (Nerd)

A ok... (Nod) But, when we write an algorithm, we have to change firstly [m]Q->next->prev[/m] and then [m]Q->next[/m], right? (Thinking)
 
evinda said:
A ok... (Nod) But, when we write an algorithm, we have to change firstly [m]Q->next->prev[/m] and then [m]Q->next[/m], right? (Thinking)

That is only necessary when you write in an actual programming language like C.
In an "algorithm" you can use this notation for simultaneous assignment. (Nod)
 
I like Serena said:
That is only necessary when you write in an actual programming language like C.
In an "algorithm" you can use this notation for simultaneous assignment. (Nod)

I understand... Thank you! (Smile)
 
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