alingy1 said:http://www.wolframalpha.com/input/?i=integral+of+1/(3x+1)=1/3ln(x+1/3)
Why is 1/3 ln((x+1/3)) not right?
1/(3x+1)=(1/3)(1/(x+1/3))
Use substitution u=x+1/3, du=dx.
Why is this wrong?
An integral calculation problem is a mathematical problem in which the goal is to find the area under a curve or the volume of a complex shape. It involves using techniques such as integration to solve for the exact value of the area or volume.
An integral calculation problem is different from other mathematical problems because it involves finding the exact value of a continuous function, rather than just a single point or value. It also requires a different set of techniques and formulas to solve.
Integral calculation problems have a wide range of applications in various fields such as physics, engineering, economics, and statistics. Some common applications include finding the area under a velocity-time curve to determine an object's displacement, calculating the volume of a three-dimensional shape for architectural or engineering purposes, and determining the probability of a certain event occurring in statistics.
Yes, there are different methods for solving integral calculation problems, such as the fundamental theorem of calculus, integration by parts, substitution, and trigonometric substitution. The method used depends on the complexity of the problem and the type of function being integrated.
Solving integral calculation problems requires a strong understanding of calculus, particularly integration techniques and concepts such as antiderivatives, definite and indefinite integrals, and the properties of integrals. It also requires critical thinking and problem-solving skills to apply these concepts to real-world situations.