Is it possible to charge/discharge this cap fast enough?

  • Thread starter Zrakk
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    Rectifier
In summary: IGBTs are there to limit the current going to the rectifier. The IGBTs will turn off when the voltage across the capacitor is 1V, in order to reduce losses.
  • #1
Zrakk
7
1
Hello,
I'm new and I want to try asking here for any comment or suggestion.
What I have, is a common 12-pulse rectifier with its bridges in series and I included an snubber between DC-link and rectifier output. Is important to note that all inductances before the rectifier are small in order to minimize its impact on this snubber performance. Also, I cleaned the circuit from scopes and control of IGBTs in order to visualize in a better way this system.

JVdLgBc.png


The main Idea of this snubber is to give a semi-triangular shape to the current by following a reference (each snubber has it reference which is the same shape but shifted in 30°). The background theory and reason for obtaining this currents, is that doing so, I should have sinusoidal currents at the transformer's primary winding or the AC busbar which is connected this rectifier.

Now, the snubber is supposed to work like this: If output current from snubber is greater than reference, then IGBTs must be turned OFF in order to charge this capacitor and lower output current. Otherwise, if output current is less than reference IGBTs must be turned on, discharging this capacitor and increasing this current. Until now, I can only get this working using DC voltage sources instead of rectifiers (250kV each bridge) as you can see in this picture:

q3VzHkN.png


And when using a proper 12-pulse rectifier I get this.

Y0G00UK.png


Here the tracking of the reference (green) is really great but for some reason the voltage across the capacitor increases until my simulation crashes. The main idea of this snubber is to turn off both IGBTs when voltage across capacitor is aprox 1V in order to reduce losses while switching, however, if I add that condition in both cases (with DC Voltage Sources and 12-pulse rectifier) the output current from snubber (red) takes a long time to discharge when the snubber have to track the lower sections of this triangular reference.

Any suggestion or recommendation would be truly appreciated as I don't really know what to do instead of changing values of my system without knowing why.

EDIT: I'm using PLECS 3.5.2, if you think something in the logic control should be wrong then I can upload pictures of it too.
 

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  • #2
TL, DR, sorry, and Welcome to the PF.
Zrakk said:
250kV
Say what? Is that a typo (I hope)...?
 
  • #3
berkeman said:
TL, DR, sorry, and Welcome to the PF.

Say what? Is that a typo (I hope)...?

In a nutshell, this capacitor should be able to charge and discharge to follow a triangular reference. Also, this snubber is supposed to be used in a HVDC system so that's why for the DC Voltage Sources case I used 250kV and of course elements like IGBTs is just to represent an idea as it is impossible for a real IGBT to hold a huge voltage.

EDIT: you can think of this exact system but for a much lower voltage... my questions remains the same as no matter what voltage level I use at AC side, I can't achieve what I want.
 
  • #4
You know what you mean but there are still two many vagiaries.
Zrakk said:
What I have, is a common 12-pulse rectifier with its bridges in series and I included an snubber between DC-link and rectifier output.
Which rectifier output?
Please refer to what you might mean by "snubbers" by the unique component ID's involved.
Label the DC link. Is that also a common ground reference?
 
  • #5
Baluncore said:
You know what you mean but there are still two many vagiaries.

Which rectifier output?
Please refer to what you might mean by "snubbers" by the unique component ID's involved.
Label the DC link. Is that also a common ground reference?

Both rectifiers. I call 'snubber' that IGBT+DIODE+CAP configuration (D1, D2, IGBT1, IGBT2 and C). The DC Link will be a +/- link at the right of those 300uF cap in a way that the AC component of this "triangular current" circulates through 'Diode Rectifier', 'Snubber 1' and C1.
 
  • #6
Capacitors C1 and C2 suggest you want to produce a stable DC output voltage.

Why do you have inductors before the 6PH diode rectifier, but none after the diode rectifier?
An inductive choke there will limit the current to a triangular waveform.

Why do you need the IGBTs shown? Are you trying to regulate the output voltage or current?
Are you trying to make a switching voltage regulator?
 
  • #7
Baluncore said:
Capacitors C1 and C2 suggest you want to produce a stable DC output voltage.

Why do you have inductors before the 6PH diode rectifier, but none after the diode rectifier?
An inductive choke there will limit the current to a triangular waveform.

Why do you need the IGBTs shown? Are you trying to regulate the output voltage or current?
Are you trying to make a switching voltage regulator?

That's correct. This circuit is 'supposed' to represent the rectifier side of a HVDC link. Those inductors before both rectifiers represent the transformer's inductance (as it more easy to modify on software instead of going into the transformer).

Those IGBTs are for discharging the capacitor and increase the output current of this circuit (to follow the aforementioned triangular reference). Using IGBT's I can control via gate signalling when the capacitor must be discharged (when real current < triangular reference) and then, when the current is greater than triangular reference it turns off (ideally, when voltage across capacitor is close to zero volts).

4oQX9RT.png


What I'm trying to do, is to regulate the output current of THIS circuit (igbts+diodes+capacitor) in order to obtain triangular currents. However, this AC components will go through C1 and C2. https://drive.google.com/file/d/1Lax5r6jgsIodX7IJ4hEeZWZXWTOK5Eu3/view?usp=sharing I uploaded the original paper that includes the theory behind this triangular currents upstream the stable DC output voltage in C1 and C2.
 

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  • #8
Interesting circuit. I've only skimmed the paper you referenced and I've probably missed a bunch of details, but what jumps out at me is Fig. 3. Your waveform images seem to show Iref as a Triangle waveform, but Fig. 3 shows Iref as a Sine shape, with Triangular Iswitch being the resultant switch current. Could this be the source of your problem?

Please let us know any further results you get.

Cheers,
Tom
 
  • #9
When fed from a 3PH supply and another shifted 30 deg by a zig-zag transformer, the output ripple is only about 6 volts in 4727.V, and the current is likewise remarkably stable. I see no reason for the IGBTs.

The output of full-wave rectified 3PH star is the same as a full-wave rectified 60° shifted delta. That will not cancel when the two are added in series.
Maybe your simulation used the 60° phase shift of a delta connected transformer, rather than the 30° phase shift of a zig-zag transformer.

two.jpg

one.jpg
 

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  • #10
Could it be something simple like not having anti parallel diodes on the IGBT model?

Since its a model you can also use a mosfet to test if that is the problem, or put the diodes into the model.
 

1. Can a capacitor be charged or discharged quickly?

Yes, it is possible to charge or discharge a capacitor quickly. The speed at which a capacitor can be charged or discharged is determined by the capacitance, resistance, and voltage of the circuit.

2. Is there a limit to how fast a capacitor can be charged or discharged?

There is a limit to how fast a capacitor can be charged or discharged, which is determined by the capacitance of the capacitor and the internal resistance of the circuit. Attempting to charge or discharge a capacitor too quickly can result in damage to the capacitor or other components in the circuit.

3. What factors affect the charging and discharging speed of a capacitor?

The charging and discharging speed of a capacitor is affected by the capacitance, resistance, and voltage of the circuit. A higher capacitance or lower resistance will result in a slower charging or discharging speed, while a higher voltage will result in a faster charging or discharging speed.

4. Can a capacitor be charged or discharged faster with a larger voltage?

Yes, a capacitor can be charged or discharged faster with a larger voltage. This is because a higher voltage creates a larger potential difference between the plates of the capacitor, allowing for a faster flow of charge.

5. How can a capacitor be charged or discharged more quickly?

A capacitor can be charged or discharged more quickly by using a circuit with a lower internal resistance, increasing the voltage of the circuit, or using a capacitor with a higher capacitance. However, it is important to ensure that these methods do not exceed the safe operating limits of the capacitor to avoid damaging it.

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