- #1
carl fischbach
Lets say you take a 30 gram bullet and fire it out
of a barrel that gives the bullet a linear velocity of 86.6% of c
with no angular velocity.
Now it's mass would be 60 grams. Next you
accelerate the bullet angularly while it is in
motion,with a force that in no way affects the
bullet's linear motion.Assuming mechanical
failure isn't allowed, the bullet is angularly
accelerated until the bullet's mass becomes
90 grams. The bullet's linear velocity of 86.6%
of c won't be affected, since the angular
acceleration force acted perpendicular to the bullet's
linear motion.Relativistic momentum of the
bullet is given by p=gamma*(rest mass bullet)*v.
You now have a case where linear momentum of the
bullet at 86.6% of c,before angular acceleration
is(p=2*.03*.866*c),after angular acceleration of
the bullet,the linear momentum is now
(p=3*.03*.866*c).Why aren't these 2 momentums
equal since linear momentum must be conserved?
of a barrel that gives the bullet a linear velocity of 86.6% of c
with no angular velocity.
Now it's mass would be 60 grams. Next you
accelerate the bullet angularly while it is in
motion,with a force that in no way affects the
bullet's linear motion.Assuming mechanical
failure isn't allowed, the bullet is angularly
accelerated until the bullet's mass becomes
90 grams. The bullet's linear velocity of 86.6%
of c won't be affected, since the angular
acceleration force acted perpendicular to the bullet's
linear motion.Relativistic momentum of the
bullet is given by p=gamma*(rest mass bullet)*v.
You now have a case where linear momentum of the
bullet at 86.6% of c,before angular acceleration
is(p=2*.03*.866*c),after angular acceleration of
the bullet,the linear momentum is now
(p=3*.03*.866*c).Why aren't these 2 momentums
equal since linear momentum must be conserved?