- #1
mooncrater
- 217
- 18
Homework Statement
There is a part of solution of a question which says that:
##cot|cot^{-1}x|=cot cot^{-1}x=x##
Homework Equations
The Attempt at a Solution
If we put ##x=-1## in this equation then ##cot^{-1}(-1)=-\pi /4## which will have a modulus =##\pi /4##. And ##cot \pi /4=1## which is not equal to the ##x## we took. So this equation seems wrong to me. Am I correct here?