- #1
Fedor
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Homework Statement
A ball approaches a tennis racquet with a velocity of [tex]30ms^-^1[/tex]. The racquet gives it an average acceleration of [tex]5000ms^-^2[/tex] for [tex]0.02s[/tex] in the opposite direction to it's initial velocity. What is the velocity of the ball after leaving the racquet and how far does the ball travel while undergoing this acceleration?
Homework Equations
Where: s=displacement, u=initial velocity, v=final velocity, a=acceleration, t=time
[tex]
v=u + at
[/tex]
[tex]
s=(1/2)(u+v)t
[/tex]
[tex]
v^2=u^2+2as
[/tex]
[tex]
s=ut+(1/2)at^2
[/tex]
The Attempt at a Solution
What confuses me about this question is the wording used. So forgive me if it confuses you too but I've written the question the same as it was wrote. I don't want to say specifically what part of the question is confusing as I think it'd be best for you to interpret the question and answer without me influencing you.
So can somebody answer this 2 part question? I'd be happy to show how I think it's worked out but as I said earlier, I think the question can be interpreted in a number of ways so I'll wait for an answer before I give my interpretation.
Thanks a lot, I really appreciate all the feedback.