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_Bd_
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Homework Statement
If A is a skew symetric matrix (such that A^T = -A)
and A is an nxn matrix with n being an odd number proove that det(A) = 0
The Attempt at a Solution
all I can think of is
det(A) = det(A^T)
letting c = -1 det(cA) = c^ndet(A)
but I can't get anymore connections to proove this. . .I tried doing some random example of a 3x3 skew symetric matrix but I didnt get a det=0. . .so I have no clue how to go about this problem!