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roam
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Homework Statement
I am trying to use the equation ##B_{dip} (r) = \nabla \times A## to find the magnetic field due to a dipole at the origin pointing in the z direction (where A is the magnetic vector potential).
The correct answer should be:
##B_{dip} (r) = \frac{\mu_0 m}{4 \pi r^3} \ (2 cos \theta \ \hat{r} + sin \theta \ \hat{\theta})##
But I'm unable to get this expression. I can't see how they got the part in the bracket.
Homework Equations
In spherical coordinates:
##A_{dip} (r) = \frac{\mu_0}{4 \pi} \frac{m sin \theta}{r^2} \hat{\phi}## ... (1)
Curl:
The Attempt at a Solution
So we only need to use the ##\hat{\phi}## term from the curl equation. Substituting (1) into (2), we obtain:
##\nabla \times A= \frac{1}{r}\left( \left( \frac{\partial}{\partial r} \left( \frac{r \mu_0 m \ sin \theta}{4 \pi r^2} \right) \right) - \left( \frac{\partial}{\partial \theta} \left( \frac{\mu_0 m \ sin \theta}{4 \pi r^2} \right) \right) \right)##
##=\frac{1}{r} (- \frac{\mu_0 m \ sin \theta}{\pi r^2} - \frac{\mu_0 m}{4 \pi r^2} cos \theta)##
##\therefore \ B_{dip} (r) = \frac{\mu_0 m}{4 \pi r^3} (-sin \theta - cos \theta)##
So how did they get from "-sinθ - cosθ" to "2 cosθ + sinθ"? Have I made a mistake somewhere?
Any explanation would be greatly appreciated.
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