Minimum Initial Velocity for Deuterium Fusion in Center-of-Mass Frame

  • Thread starter akmphy
  • Start date
In summary, the conversation revolves around finding the minimum initial velocity of two deuterium nuclei in order to overcome the Coulomb force and achieve fusion. The necessary distance for fusion is 1 × 10−14 m. The permittivity of free space, mass and charge of protons, neutrons, and electrons are provided. The question asks for the answer in units of m/s. The homework equation provided is 2mv.5(v)=ka/rm and the separation between the nuclei is denoted as r. The person asking for help does not know how to begin and is looking for assistance.
  • #1
akmphy
16
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Please help me with this!

Two deuterium nuclei overcome the Coulomb
force of repulsion and attain the necessary
1 × 10−14 m distance for fusion.
What is the minimum initial velocity of
each nuclei, as measured in the center-of-
mass frame? The permittivity of free space
is 8.85419 × 10−12 C2/N · m2, the mass of a
proton is 1.67262 × 10−27 kg, the mass of a
neutron 1.67493 × 10−27 kg and the charge
on an electron −1.60218 × 10−19 C.
Answer in units of m/s.

2. Homework Equations
I do not know how to do this:
2mv.5(v)=ka/rm
r=separation b/w nuclei


3. The Attempt at a Solution
I am more than willing to work this out with someone. Usually I have an attempt; however, I believe I have no where to begin. Any help is appreciated.
 
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  • #2


What's the mass of a deuterium nucleus? What's its charge?

What's the potential energy due to the Coulomb field for two deuterium nuclei at the specified separation?
 

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