- #1
volodymyr379
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- Homework Statement
- Student A, of mass 100 kg, stands 2 meters from the center of a circular platform which is free to rotate on frictionless bearings. Student B, not standing on the platform, tosses student A a baseball of mass 0.09 kg, which reaches student A with a velocity of 20 m/s directed perpendicular to the line joining student A and the center of the platform. If the platform has a moment of inertia 200 kg·m^2, what is its approximate angular velocity after student A catches the baseball?
- Relevant Equations
- mb*vb*r= (Ip+Is)*ω , where mb - mass of the ball, vb - speed of the ball, Ip and Is - moments of inertia of the platform and the student respectively.
E_kin = E_rot
(mb*v^2) = ((Ip+Is)*ω^2)/2
When I solved the problem using the conservation of angular momentum, I have got the correct result (ω = 0.006 rad/s). However, when I tried to find the answer using the conservation of energy the result was incorrect and I do not understand why.