- #1
AfronPie
Homework Statement
Attached.
Homework Equations
I=mr^2, I=(1/12)m*l^2 for a rod.
The Attempt at a Solution
Part A I got by doing I=(1/12)3.5*(2.6)^2+2*.7*1.3^2 (I added the moment of inertia of the rod and the balls). Part B since the axis is on one of the balls, I thought we don't include that ball in the calculations. So the rod stays, (1/12)m*l^2 and we add the other .7 kg ball which is 2.6m away. So I_total=(1/12)3.5*2.6^2+.7(2.6)^2=6.7 kg*m^2. However that isn't the right answer. Can someone please explain to me where I went wrong. Any help is greatly appreciated.