Motion in two dimension problem. Range and Height.

In summary, the conversation is about finding the maximum height, time in air, and horizontal distance of a rocket launched at a speed of 30.0 m/s at an angle of 40 degrees above the horizontal. The relevant equations are listed and the person asking for help has divided the motion into two phases but is having trouble finding the time and final position. They are not allowed to use the direct formula and have since figured out how to solve the problem.
  • #1
greg_jones20
3
0

Homework Statement


A rocket is launched from level ground with a speed of 30.0 m/s at an angle of 40 degrees above the horizontal. Find:

a) Maximum height reached by the rocket.
b) The time rocket is in the air.
c) the horizontal distance where the rocket lands.


Homework Equations


V= Vo + at
V^2 = Vo^2 + 2a(X-Xo)
X= Xo +Vo(t) + (1/2)at^2

The Attempt at a Solution



Divided the entire motion into two phases 1st and 2nd, Got x and y components of everything. Can't seem to find the time and final position anyway. I am not allowed to use the direct formula for Range and Height.
Help please!
 
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  • #2
You'll have to show some of your work so that we'll know where to help. What are your "phases"?
 
  • #3
Well I meant the two different phases for first and second half part of its motion.

Never mind I figured out how to solve this problem.
Thanks anyway.
 

Related to Motion in two dimension problem. Range and Height.

1. What is the difference between motion in one dimension and motion in two dimensions?

Motion in one dimension refers to the movement of an object along a straight path, while motion in two dimensions involves the movement of an object along two perpendicular axes, such as horizontal and vertical. In other words, in motion in two dimensions, an object is not restricted to moving in a straight line.

2. How do you calculate the range of an object in a two-dimensional motion problem?

The range of an object in a two-dimensional motion problem is the horizontal distance it travels before returning to its initial height. To calculate the range, you can use the formula: R = Vx * t, where Vx is the initial horizontal velocity and t is the total time of flight.

3. What factors affect the height of an object in a two-dimensional motion problem?

The height of an object in a two-dimensional motion problem is affected by its initial velocity, the angle at which it is launched, and the force of gravity. These factors determine the object's trajectory and how high it will go before reaching its peak height and falling back down.

4. Can an object have different ranges and heights in a two-dimensional motion problem?

Yes, an object can have different ranges and heights in a two-dimensional motion problem depending on the initial conditions, such as its initial velocity and launch angle. These variables can be manipulated to achieve different trajectories and therefore different ranges and heights.

5. How can you use the range and height equations to solve for other variables in a two-dimensional motion problem?

In a two-dimensional motion problem, the range and height equations can be used to solve for other variables such as time, initial velocity, and launch angle. By rearranging the equations and plugging in known values, you can solve for the unknown variable and further analyze the motion of the object.

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