Need help understanding this thermo. derivation

  • Thread starter Thread starter mdawg467
  • Start date Start date
  • Tags Tags
    Derivation Thermo
AI Thread Summary
The discussion focuses on deriving the expression for the partial derivative (\frac{\partial T}{\partial P})s in terms of temperature (T), specific volume (V), heat capacity at constant pressure (Cp), thermal expansion coefficient (α), and isothermal compressibility (κT). The user struggles with the notation and steps in the book's derivation. Another participant offers clarification by providing a more straightforward version of the derivation using ordinary partial derivative notation. The exchange highlights the complexity of the derivation and the need for clearer explanations in academic texts. Overall, the conversation emphasizes the importance of understanding notation in thermodynamic expressions.
mdawg467
Messages
14
Reaction score
0
Im trying to understand this concept of deriving an expression for (\frac{\partial T}{\partial P})s in terms of T, V, Cp, \alpha, and \kappaT

(\frac{\partial T}{\partial P})s is evaluated by measuring the temperature change and the specific volume change accompanying a small pressure change in a reversible adiabatic process.

I attached the derivation that the book does, but I cannot follow it. Any help would be greatly appreciated!

Thanks
 

Attachments

  • 20130406_173018-1.jpg
    20130406_173018-1.jpg
    17.8 KB · Views: 619
Science news on Phys.org
There are a lot of steps in that simple looking derivation. Where are you lost?
 
Don't understand the notation in your thumbnail, but append my derivation, expressed in ordinary partial derivative notation.
 

Attachments

  • Thermod formula.jpg
    Thermod formula.jpg
    12.2 KB · Views: 836
Philip Wood said:
Don't understand the notation in your thumbnail, but append my derivation, expressed in ordinary partial derivative notation.

Thanks dude, I was getting lost with the notation as well. This helps out big time.. Not sure what the book was doing lol.
 
Thread 'Thermo Hydrodynamic Effect'
Vídeo: The footage was filmed in real time. The rotor takes advantage of the thermal agitation of the water. The agitation is uniform, so the resultant is zero. When the aluminum cylinders containing frozen water are immersed in the water, about 30% of their surface is in contact with the water, and the rest is thermally insulated by styrofoam. This creates an imbalance in the agitation: the cold side of the water "shrinks," so that the hot side pushes the cylinders toward the cold...
Back
Top