Normal modes of continuous systems

In summary: You will have to use the sketch to estimate displacements at various points for the two modes (interpolating if needed).
  • #1
hobmarcus
10
0

Homework Statement


A room has two opposing walls which are tiled. The remaining walls, floors, and ceiling are lined with sound-absorbent material. The lowest frequency for which the room is acoustically resonant is 50Hz.

(a) Complex noise occurs in the room which excites only the lowest two modes, in such a way that each mode has its maximum amplitude at t=0. Sketch the appearance, fro each mode separately, of the displacement versus at t=0,t=1/200sec, and 1/100 sec.

(b) It is observed that the maximum displacement of dust particles in the air (which does not necessarily occur at the same time at each position.) at various points between walls is as follows:
Screen Shot 2015-02-21 at 8.18.02 PM.png


what are the amplitude of each of the two separate modes?

Homework Equations


Screen Shot 2015-02-21 at 8.21.55 PM.png

[/B]

The Attempt at a Solution



for part a, the lowest two modes are just simply 50hz and 100hz?
if yes, the equation of the complex noise is it just x=2Acos(50πt)cos(150πt)
Since ω=2πf and x=2Acos((ω12)/2)cos((ω12)/2)

for part b, I really have no clue how to approach.

Any tips or explanations, please. I appreciate any helps.
 
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  • #2
Hello Marcus, welcome to PF :smile:

Yes, the lowest mode is 50 Hz; the exercise text says so. So the next is 100 Hz.
I do wonder if you have a good idea of what happens.
I thought white noise has a flat frequency spectrum and complex noise has a Gaussian frequency spectrum -- anyway, you aren't after the equation of the noise but after the displacement as a function of (missing in problem statement. x ?) for three moments in time.

The tiles reflect the sound waves and for 50 and 100 Hz there is constructive interference of the waves going back and forth and a standing wave pattern emerges. You get displacements ##\xi(x,t) = \xi_0 \; \cos(\omega t)\; sin(kx)## for ##\omega = 2\pi \;50## rad/s and similarly for ##\omega = 2\pi \;100## rad/s (with its own ## \xi_0## !) and the exercise wants you to fill in the three times for each of the modes separately and sketch. Can you post your sketches ?

Once part a) is clear and understood, part b) will become easier to deal with.
 

What are normal modes of continuous systems?

Normal modes of continuous systems refer to the characteristic vibration patterns of a continuous system, such as a string or beam, that occur when the system is disturbed from its equilibrium position.

How are normal modes calculated?

Normal modes are calculated by solving the governing differential equations for the system, typically using methods such as the finite element method or the method of separation of variables.

Why are normal modes important in engineering?

Normal modes are important in engineering because they help us understand and predict the behavior of continuous systems, which are commonly encountered in structures, machines, and other engineering systems.

How are normal modes related to natural frequencies?

Normal modes and natural frequencies are closely related, as each normal mode has a corresponding natural frequency at which the system will vibrate. The natural frequencies can be determined by analyzing the normal modes of the system.

Can a continuous system have an infinite number of normal modes?

Yes, a continuous system can have an infinite number of normal modes. This is because there are an infinite number of ways in which the system can vibrate, each with a different pattern and frequency.

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