- #1
Sarah0001
- 31
- 1
- Homework Statement
- An egg is dropped at rest from a tree
c) an egg strikes the ground and is brought to a stop in a distance
of 1 mm. Assuming a mass of 20 g for the egg calculate the force
required. (You may assume a constant braking force).
I am confused on the visual picture of what is happening, when the is 'brought to a stop in a distance of 1 mm' from the moment it strikes the ground.
- Relevant Equations
- Know velocity of egg when it reaches the ground is 19.79 m/s Know
can use suvat or energy conservation 1/2mv^2=Fd
s=1 *10^-3 v^2 = u^2 + 2as a = v^2 - u^2 / 2*s = - 195 822.05 m/s^2
u=19.79 m/s F= 20*10^-3 *195 822.05 = 4000 N (1 s.f)
v=0
a=?or 1/2mv^2=Fd ----> F= mv^2/2d = 4000 (1 s.f)With either method, I am still confused on the visual picture of what is happening, when the egg is 'brought to a stop in a distance of 1 mm'. I have a few ideas: Does this mean that the egg bounces from the ground with initial velocity 19.79 m/s to zero at 1 mm off the ground? Or does it mean the egg possibly deforms upon hitting the ground? Or the ground deforms very slightly so the egg moves a distance of 1mm upon striking it? I'm quite confused at what I'm supposed to picture here.
u=19.79 m/s F= 20*10^-3 *195 822.05 = 4000 N (1 s.f)
v=0
a=?or 1/2mv^2=Fd ----> F= mv^2/2d = 4000 (1 s.f)With either method, I am still confused on the visual picture of what is happening, when the egg is 'brought to a stop in a distance of 1 mm'. I have a few ideas: Does this mean that the egg bounces from the ground with initial velocity 19.79 m/s to zero at 1 mm off the ground? Or does it mean the egg possibly deforms upon hitting the ground? Or the ground deforms very slightly so the egg moves a distance of 1mm upon striking it? I'm quite confused at what I'm supposed to picture here.