Oscillation of nonrelativistic Strings

In summary, the conversation discusses the calculation of the horizontal force dFhorizontal of a string and its comparison to the vertical force dFvertical responsible for transverse oscillations. The equations involved are substituted and exchanged to show that the horizontal force is much smaller than the vertical force for small oscillations. The suggestion is made to express the forces in terms of y(x) and its derivatives and compare them using the assumption of small oscillations.
  • #1
moriheru
273
17

Homework Statement


Calculate the horizontal force dFhorizontal of a string .Show that for small oscillations this force is much smaller than the vertical force dFvertical responsible for the transverse oscillations.
[I apolagize for the way the equations are written]

Homework Equations



dFvertical=T0dy/dx*-T0dy/dx*1
*for x+dx *1 for x

T0(d^2 y/d^2 x)dx=(μ0dx)d^2 y/dt^2

3. The Attempt at a Solution

1.substituting y+dy and y for x+dx and x; substituting dx/dy for dy/dx for horizontal oscillation.
dFhorizontal=T0dx/dy*-T0dx/dy*1
*for y+dy *1 for y
2.exchanging d^2 y/ dx^2 with d^2 x/dy^2 and dx with dy...

T0 (d^2 x/dy^2) dy= (μ0dx)(d^2 x/dt^2)

This is as far as I get. I don't know how to show that the horizontal force is smaller than the vertical force for small oscillations.

Thanks for any clarifications and corrections.
 
Last edited:
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  • #2
I would instead express the forces (both horizontal and verical) in terms of y(x) and its derivatives wrt x. You can then compare the two with the assumption of small oscillations giving you dy/dx << 1.
 

1. What is the concept of oscillation in nonrelativistic strings?

Oscillation in nonrelativistic strings refers to the periodic back-and-forth motion of a string under tension. This motion is caused by the interplay between the restoring force of tension and the inertia of the string. In other words, when the string is pulled or displaced from its equilibrium position, it will exert a force that tries to bring it back to its original position, causing it to oscillate.

2. What factors affect the oscillation of nonrelativistic strings?

The oscillation of nonrelativistic strings is affected by several factors, including the tension of the string, its length, and its mass. Higher tension and shorter length result in faster oscillations, while a heavier string will oscillate more slowly.

3. What is the difference between standing waves and traveling waves in nonrelativistic strings?

Standing waves occur when two identical waves traveling in opposite directions interfere with each other, resulting in a stationary pattern of oscillation. Traveling waves, on the other hand, move through a medium without interfering with each other. In nonrelativistic strings, standing waves are formed when the string is fixed at both ends, while traveling waves are formed when one end of the string is held fixed and the other end is free.

4. How are the frequency and wavelength of oscillation related in nonrelativistic strings?

Frequency and wavelength are inversely related in nonrelativistic strings. This means that as the frequency of oscillation increases, the wavelength decreases and vice versa. This relationship is described by the equation f = v/λ, where f is the frequency, v is the speed of the wave, and λ is the wavelength.

5. Can the oscillation of nonrelativistic strings be used to measure tension or mass?

Yes, the oscillation of nonrelativistic strings can be used to indirectly measure tension and mass. By measuring the frequency and wavelength of the oscillation, the speed of the wave can be calculated. Using this speed and other known factors, such as the length of the string, the tension or mass can be determined through mathematical equations.

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