- #1
superwolf
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Homework Statement
2. The attempt at a solution
a) The particle seems to be 50 nm in diameter, so
[tex]
D = \frac{k_BT}{6 \pi \eta R} = 4.4E-12 m^2s^{-1}
[/tex]
b)
[tex]
j_{diff}=-D\frac{dc}{dx} = -4.4E-12 \cdot \frac{dc}{dx}
[/tex]
I don't know what to do next...Can I assume [tex]c(x) = c_0x[/tex]? In that case,
[tex]
j_{diff} = -4.4E-12 c_0
[/tex]
Is this correct? What are the units?
And how to do c)?
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