- #1
metal_maniac
- 4
- 0
I'm currently taking a modern physics course, I came across this problem which really threw me off guard:
Three spaceships A, B, and C are in motion as shown in the figure. The commander on ship B observes ship C approaching with a relative velocity of 0.83c. The commander also observes ship A, advancing in the rear, with a relative velocity of 0.48c. As measured by commander on ship B, at what speed is ship A approaching ship C?
Attempt at a solution: I used the transformations equations which resulted in a value of 0.94c.
observed velocity = [(-0.83c) - 0.48c]/[1-(0.83c*0.48c/c^2)] = 0.937c
0.94c was one of the possible answers so I picked it... it was wrong.
The correct answer was 1.3c.
Is this even possible?
I do suppose that someone with no knowledge in physics would just add the two velocities like it was Galilean transformations, but we're taking about the commander of a ship, pretty sure he wouldn't just add them together.
Is this just a badly written question or am I missing some things in my understanding? Any help is appreciated!
Thank you
Three spaceships A, B, and C are in motion as shown in the figure. The commander on ship B observes ship C approaching with a relative velocity of 0.83c. The commander also observes ship A, advancing in the rear, with a relative velocity of 0.48c. As measured by commander on ship B, at what speed is ship A approaching ship C?
Attempt at a solution: I used the transformations equations which resulted in a value of 0.94c.
observed velocity = [(-0.83c) - 0.48c]/[1-(0.83c*0.48c/c^2)] = 0.937c
0.94c was one of the possible answers so I picked it... it was wrong.
The correct answer was 1.3c.
Is this even possible?
I do suppose that someone with no knowledge in physics would just add the two velocities like it was Galilean transformations, but we're taking about the commander of a ship, pretty sure he wouldn't just add them together.
Is this just a badly written question or am I missing some things in my understanding? Any help is appreciated!
Thank you