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ProPatto16
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Homework Statement
hypothetical one electron searsium element. n=-20eV, n2=-10eV, n3=-5eV, n4=-2eV. photon emission n3>n2 and n3>n1 will eject photoelectrons from unkown metal, but photon emitted from n4>n3 will not. what are the limits (max and min values) of work function of the metal.
The Attempt at a Solution
photon emitted will have energy of 3eV. which is 4.806*10-19 J. which equates to frequency of 7.25*1014 Hz.
work function = hf0 where f0 is minimum freq required to emit electron which is what we found.
so work function = 7.25*1014 x 6.626*10-34
= 4.806*10-19
so the work function of the metal is 3eV. but how is there a max and a min?