Piston in a tube connected to a vessel filled with air

In summary, the conversation is about a problem involving a piston in a tube connected to a vessel filled with air. The air behaves as an ideal gas and the product of pressure and volume raised to a constant power is constant. The equation of motion for the piston is related to the gas volume when the piston is at a certain position, and there is no friction. The person is seeking clarification on the equation and is asking for insight on the force on the piston from the vessel.
  • #1
Ben Harris
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1
Hi there, i have been working with a problem the past few days and have a hard time with some of the assumptions being made.
The problem involves a piston in a tube which is connected to a vessel filled with air.
The air behaves as an ideal gas to which the product PV^ζ is a constant.
The piston is released from y=0 at t=0 and we are asked to show that the equation of motion for the piston can be expressed as the attached photo shows:

upload_2019-2-3_20-57-39.png


V(y) is gas volume when piston is at y position. There is no friction.

I don't understand what the [([V][/0]/[V[/y])[/ζ] is and how it came to be like this.

this is where i am at with it:

upload_2019-2-3_21-3-12.png


if you could provide some insight to what the force on the piston from the vessel involves it would be much appreciated.

Thank you :)
 

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  • #2
Since ##PV^{\gamma} = const## then $$P_0V_0^{\gamma} = PV^{\gamma} \rightarrow P = P_0 \left( \frac {V_0}{V} \right) ^{\gamma}$$
 
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What is a piston in a tube connected to a vessel filled with air?

A piston in a tube connected to a vessel filled with air is a common setup used in experiments to demonstrate the principles of air pressure and gas laws. It consists of a tube filled with air, connected to a vessel at one end and a piston at the other end.

How does the piston in a tube connected to a vessel filled with air work?

The piston in this setup can move freely up and down the tube. When the piston is pushed down, it compresses the air in the tube, increasing the air pressure. When the piston is pulled up, the air expands and the pressure decreases. This demonstrates the relationship between volume and pressure in gases.

What happens to the air pressure when the piston is pushed down?

When the piston is pushed down, the volume of the air decreases while the number of air particles remains the same. This causes the air particles to collide with each other and the walls of the tube more frequently, resulting in an increase in air pressure.

How does the piston in a tube connected to a vessel filled with air demonstrate Boyle's Law?

Boyle's Law states that at a constant temperature, the volume of a gas is inversely proportional to its pressure. In this setup, when the piston is pushed down and the volume of the air decreases, the pressure increases. When the piston is pulled up and the volume increases, the pressure decreases. This shows the inverse relationship between volume and pressure in gases.

What other gas laws can be demonstrated with the piston in a tube connected to a vessel filled with air?

In addition to Boyle's Law, this setup can also demonstrate Charles's Law, which states that at a constant pressure, the volume of a gas is directly proportional to its temperature. By heating the air in the vessel, the volume of the air increases, showing the direct relationship between volume and temperature in gases.

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