Plot of y = \dfrac{4}{9}(x-3)(x+3)

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  • Thread starter karush
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In summary, the problem is that [right] is treated as a special code to align text to the right, so you need to use extra spaces.
  • #1
karush
Gold Member
MHB
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$y = \dfrac{4}{9}(x-3)(x+3)$

ok I can't seem to write tikz to plot this

\begin{tikzpicture}[scale=0.50]
%preamble \usepackage{pgfplots}
\begin{axis}[xmin=-3.5, xmax=3.5, ymin=-5, ymax=5, axis lines=middle, ticks=none]
\addplot[
draw = black, smooth, ultra thick,
domain=-4:4,
] {exp((4/9)*(x^2-9)}
foreach \x in {-3,3} { (axis cs:{\x},0) node[below left] {\x} };
\end{axis}
\end{tikzpicture}
$y = \dfrac{4}{9}(x-3)(x+3)$
 
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  • #2
this plots in overleaf but not here?ut\begin{tikzpicture}[xscale=1,yscale=1]
%preamble \usepackage{pgfplots}
\begin{axis}[xmin=-4, xmax=4, ymin=-5, ymax=5, axis lines=middle, ticks=none]
\addplot[draw = blue, smooth, ultra thick,domain=-4:4,] {(4/9)*(x^2-9))};
\draw[thin][fill][red] (-3,0) circle (.2);\node [below] at (-3.2,-.5) {(-3,0)};
\draw[thin][fill][red] (3,0) circle (.2);\node [below] at (3.2,-.5) {(3,0)};
\draw[thin][fill][red] (0,-4) circle (.2);\node
at (.3,-4.3) {(0,-4)};
\end{axis}
\end{tikzpicture}
$\boxed{y=\dfrac{4}{9}(x^2-9)}$​
 
  • #3
It seems to plot just fine for me. What is the problem?
 
  • #4
sorry actually its this one...

$\boxed{y=\dfrac{4}{9}(x^2-9)}$
\begin{tikzpicture}[xscale=1,yscale=1]
%preamble \usepackage{pgfplots}
\begin{axis}[xmin=-4, xmax=4, ymin=-5, ymax=3, axis lines=middle, ticks=none]
\addplot[draw = blue, smooth, ultra thick,domain=-4:4,] {(4/9)*(x^2-9))};
\draw[thin][fill][red] (-3,0) circle (.2);\node [below] at (-3.2,-.5) {(-3,0)};
\draw[thin][fill][red] (3,0) circle (.2);\node [below] at (3.2,-.5) {(3,0)};
\draw[thin][fill][red] (0,-4) circle (.2);\node
at (.3,-4.3) {(0,-4)};
\end{axis}
\end{tikzpicture}​
 
  • #5
karush said:
sorry actually its this one...

Unfortunately this forum treats [right] as a special code to align text to the right.
A work around is to use extra spaces and make it [ right ].
Then we get:

\begin{tikzpicture}[xscale=1,yscale=1]
%preamble \usepackage{pgfplots}
\begin{axis}[xmin=-4, xmax=4, ymin=-5, ymax=3, axis lines=middle, ticks=none]
\addplot[draw = blue, smooth, ultra thick,domain=-4:4,] {(4/9)*(x^2-9))};
\draw[thin][fill][red] (-3,0) circle (.2);\node [below] at (-3.2,-.5) {(-3,0)};
\draw[thin][fill][red] (3,0) circle (.2);\node [below] at (3.2,-.5) {(3,0)};
\draw[thin][fill][red] (0,-4) circle (.2);\node [ right ] at (.3,-4.3) {(0,-4)};
\end{axis}
\end{tikzpicture}
 

1. What is the equation for the given plot?

The equation for the given plot is y = 4/9(x-3)(x+3).

2. What is the degree of the polynomial in the equation?

The degree of the polynomial in the equation is 2.

3. How many solutions does this equation have?

This equation has 2 solutions, since it is a quadratic equation with a degree of 2.

4. What is the y-intercept of this equation?

The y-intercept of this equation is 0, as the equation does not contain a constant term.

5. What is the significance of the points where the graph intersects the x-axis?

The points where the graph intersects the x-axis, also known as the roots or zeros of the equation, represent the solutions to the equation. These points are where the value of y is equal to 0.

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