- #1
RoboNerd
- 410
- 11
Homework Statement
Five identical masses of mass M are suspended by a spring stretched a distance of L. If three of the masses are removed, what is the potential energy stored in the spring?
1) (4 / 25) * M * g * L
2) (2 / 5) M * g * L^2
3) (5 / 2) * M g * L
4) (4 / 25 ) * M * g L^2
5) 5 * M * g * L
Homework Equations
Fspring = -k * x
The Attempt at a Solution
Hi everyone. I get 2 to be the answer while my solutions manual says that 4 is correct. I suspect the solutions manual is wrong, but I wanted to get someone's opinion on this first.
So firstly, I got the value of the "K" for the spring:
Fspring = Fg of the masses
k * x = 5 * M * g
k = (5 * M * g) / LThen, I got the amount of stretch of the spring with only two masses.
Fspring = Fg of the masses
k * d = 2 * M * g
[ (5 * M * g) / L ] * d = 2 * M * g
solved for d = (2 /5 ) * L.
Then, I took equation Uspring = (1 / 2) * k * x^2.
I plugged the expressions for K and D for the stretch and I got the expression for answer 2.
Have I done something wrong?
Thanks in advance for the help!