Power Dissipated In a Linear Damper

[syberraith]

Hello,

I have a question about power dissipated in a linear damper. I know that power is equal to force times velocity, and that force is equal to the damper coefficient times velocity.

What I have to work with is the coefficient and the velocity of the damper, so the instantaneous power dissipated in the damper is the coefficient times the the square of the velocity.

My question is when integrating for power dissipated over an interval of time, should I calculate for a RMS value, or would a simple integration of C * V^2 be appropriate?

This question also applies to the systems input power, which would be calculated from torque times angular velocity. Again would an RMS or a simple figure be the proper choice?

 

[LightHero]

Thank you for your help. The power dissipated in the damper is a function of the damping coefficient and velocity. To calculate the power over an interval of time, you would need to integrate the damping coefficient times the square of the velocity. This calculation should be done using RMS values, as this will give you an accurate representation of the power dissipation over the given period of time. For the systems input power, you would need to calculate the torque times angular velocity, again using RMS values to get an accurate representation of the input power over the given period of time.