- #1
jtm
- 19
- 0
imagine a 8 letter word, how many possibilities are there to arrange letters in the alphabet (26) that start with BO(in that order) OR end with BO (in that order), if letters can be repeated?
This is my work:
1 * 1 * 26 * 26 * 26 * 26 * 26 * 26 = 26^6 +
26 * 26 * 26 * 26 * 26 * 26 * 1 * 1 = 26^6
BUT I'm not sure what the intersection is because:
do we subtract 1 or 26^4?
my logic from 26^4 is coming from BOLLLLBO <-- where L is any letter
Thank you!
This is my work:
1 * 1 * 26 * 26 * 26 * 26 * 26 * 26 = 26^6 +
26 * 26 * 26 * 26 * 26 * 26 * 1 * 1 = 26^6
BUT I'm not sure what the intersection is because:
do we subtract 1 or 26^4?
my logic from 26^4 is coming from BOLLLLBO <-- where L is any letter
Thank you!