- #1
Saladsamurai
- 3,020
- 7
I am having trouble understanding what h is in the equation for T listed below. Here is an image
The Problem: A physical pendulum consists of a uniform circular disk (of R=2.35cm) supported in a vertical plane by a pivot located a distance D=1.75cm from the center of the disk. The disk is displaced by a small angle and released. What is the period T of the resulting SHM?
Equations:
[tex]T=2\pi\sqrt{\frac{I}{mgh}}[/tex]
[tex]I=I_{cm}+mH^2[/tex]
from text [tex]I_{disk}=\frac{1}{2}MR^2[/tex]
This is where I am messing up either my algebra or what I am interpreting as h.
For the parellel-axis theorem I had [tex]I_{disk}=\frac{MR^2}{2}+MD^2[/tex] where D is the distance from the COM to the pivot.
and for h in mgh I thought the total height was h=D+R.
Am I correct about what h is? Or no? This will determine what my mistake is
Thanks
Casey
Equations:
[tex]T=2\pi\sqrt{\frac{I}{mgh}}[/tex]
[tex]I=I_{cm}+mH^2[/tex]
from text [tex]I_{disk}=\frac{1}{2}MR^2[/tex]
This is where I am messing up either my algebra or what I am interpreting as h.
For the parellel-axis theorem I had [tex]I_{disk}=\frac{MR^2}{2}+MD^2[/tex] where D is the distance from the COM to the pivot.
and for h in mgh I thought the total height was h=D+R.
Am I correct about what h is? Or no? This will determine what my mistake is
Thanks
Casey
Last edited: