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Co2
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urgent :Problem with a cylinder tank and a nozzle
Hey guys,
I have been given a problem and I really want your help cause I have some doubts:[/B]
A cylindrical tank 1.52 m in diameter and 7.62 m high contains cottonseed oil having a density of 917 kg/m3. The tank is open to the atmosphere. A discharge nozzle of inside diameter 15.8 mm and cross-sectional area A2 is located near the bottom of the tank. The surface of the liquid is located at H = 6.1 m above the center line of the nozzle. The discharge nozzle is opened, draining the liquid level from H = 6.1 m to H = 4.57 m. Calculate the time in seconds to do this.
- I have used bernoulli equation
(P1/ρg) +(v1^2/2g) + z1= (p2/ρg) +(v2^2/2g) +z2
- I assumed velocity V1 (related to the height of the oli in the tank) is very small due to the large diameter so i simply neglect it
- I assumed that Z2 elevation to be zero since the flow direction will be horizontal, and Z1 =6.1 m
- P1=P2=P atm so it's canceled
so I left with:
V2^2/ 2g= Z1 then I got the time= h/ V and here h =(6.1- 4.57)= 1.53 m
but though I got a unreasonable answer about 0.13 s
so please can you determine where is the problem in my assumptions
thank you... :shy:
Co2
Hey guys,
I have been given a problem and I really want your help cause I have some doubts:[/B]
A cylindrical tank 1.52 m in diameter and 7.62 m high contains cottonseed oil having a density of 917 kg/m3. The tank is open to the atmosphere. A discharge nozzle of inside diameter 15.8 mm and cross-sectional area A2 is located near the bottom of the tank. The surface of the liquid is located at H = 6.1 m above the center line of the nozzle. The discharge nozzle is opened, draining the liquid level from H = 6.1 m to H = 4.57 m. Calculate the time in seconds to do this.
- I have used bernoulli equation
(P1/ρg) +(v1^2/2g) + z1= (p2/ρg) +(v2^2/2g) +z2
- I assumed velocity V1 (related to the height of the oli in the tank) is very small due to the large diameter so i simply neglect it
- I assumed that Z2 elevation to be zero since the flow direction will be horizontal, and Z1 =6.1 m
- P1=P2=P atm so it's canceled
so I left with:
V2^2/ 2g= Z1 then I got the time= h/ V and here h =(6.1- 4.57)= 1.53 m
but though I got a unreasonable answer about 0.13 s
so please can you determine where is the problem in my assumptions
thank you... :shy:
Co2
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