- #1
Jenny short
- 3
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I have been trying to show that
$$\lim_{U\rightarrow\infty}\int_C \frac{ze^{ikz}}{z^2+a^2}dz = 0 $$
Where $$R>2a$$ and $$k>0$$ And C is the curve, defined by $$C = {x+iU | -R\le x\le R}$$
I have tried by using the fact that
$$|\int_C \frac{ze^{ikz}}{z^2+a^2}dz| \le\int_C |\frac{ze^{ikz}}{z^2+a^2}|
|dz|$$
I want to use the fact $$|e^{ikz}|=e^{-kU}$$
However I got really stuck after that. I would really appreciate help
$$\lim_{U\rightarrow\infty}\int_C \frac{ze^{ikz}}{z^2+a^2}dz = 0 $$
Where $$R>2a$$ and $$k>0$$ And C is the curve, defined by $$C = {x+iU | -R\le x\le R}$$
I have tried by using the fact that
$$|\int_C \frac{ze^{ikz}}{z^2+a^2}dz| \le\int_C |\frac{ze^{ikz}}{z^2+a^2}|
|dz|$$
I want to use the fact $$|e^{ikz}|=e^{-kU}$$
However I got really stuck after that. I would really appreciate help