- #1
ElleElle
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A quarterback wants to throw a football at 22.0 m/s to a receiver 31.0 m away. At what angle above the horizontal should he throw it? Assume that the receiver catches the ball at the same height that the quarterback releases it.
The answer should be 19.4° but for some reason I just cannot get it!
Please help me with the steps!
I solved for time by using: x = xi + vit + (1/2)at^2
I got t = 1.13s
Then i used x = vt to solve for velocity in the y direction. vy = 27.5 m/s (which does not seem right)
Then cos θ = adj/hyp which gives me a math error :/
The answer should be 19.4° but for some reason I just cannot get it!
Please help me with the steps!
I solved for time by using: x = xi + vit + (1/2)at^2
I got t = 1.13s
Then i used x = vt to solve for velocity in the y direction. vy = 27.5 m/s (which does not seem right)
Then cos θ = adj/hyp which gives me a math error :/