- #1
Clandry
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Show that if S = {v1, v2, . . . , vn} is a basis for Rn
and A is an n × n invertible matrix, then
S' = {Av1,Av2, . . .,Avn} is also a basis.
I need to show that:
1) Av1, Av2,...Avn are linearly independent
2) span(S)=Rn
I'm having some problems with this.
I see that S'=AS (duh)
This is what I'mthinking of doing:
c1*A*v1+...cn*A*vn=0 where c1,...cn are constants and must be zero
=A*c1*v1+...A*cn*vn=0 can I multiply by A^-1 to both sides? If so then:
=c1v1+...+cn*vn=0=span(S)
thus S' is a basis?
and A is an n × n invertible matrix, then
S' = {Av1,Av2, . . .,Avn} is also a basis.
I need to show that:
1) Av1, Av2,...Avn are linearly independent
2) span(S)=Rn
I'm having some problems with this.
I see that S'=AS (duh)
This is what I'mthinking of doing:
c1*A*v1+...cn*A*vn=0 where c1,...cn are constants and must be zero
=A*c1*v1+...A*cn*vn=0 can I multiply by A^-1 to both sides? If so then:
=c1v1+...+cn*vn=0=span(S)
thus S' is a basis?