Radiative Transfer Equation: Point Source and a Thin Lens

E}}\delta(x)\delta(z+p)L_{\mbox{in}} \left(\begin{bmatrix} \vec{r} + q\hat{s} \\ \hat{s}_{\perp} \end{bmatrix} \right) = -\frac{c}{n}\frac{1}{\mathcal{E}}\delta(x)\delta(z+p)L_{\mbox{in}} \left(\begin{
  • #1
DivGradCurl
372
0

Homework Statement



Write the Radiative Transfer Equation for an isotropic incoherent point source a distance p away from a thin lens. Assume that scattering in air can be ignored but absorption cannot be ignored.

Homework Equations



1. Radiative Transfer Equation (RTE):
[tex]\frac{dw}{dt} = \left[ \frac{dw}{dt} \right] _{\mbox{absorption}} +\left[ \frac{dw}{dt} \right] _{\mbox{emission}} + \left[ \frac{dw}{dt} \right] _{\mbox{propagation}} + \left[ \frac{dw}{dt} \right] _{\mbox{scattering}} [/tex]
which can be expressed as
[tex]\frac{dw}{dt} = \left[ -\frac{c}{n} \mu w \right] _{\mbox{absorption}} +\left[ \Xi _{p,\mathcal{E}} \right] _{\mbox{emission}} + \left[ -\frac{c}{n} \, \hat{s} \cdot \nabla w \right] _{\mbox{propagation}} + \left[ Kw \right] _{\mbox{scattering}} [/tex]
where K is an integral operator and w is the phase-space distribution function.

2. The source term can be expressed as
[tex]\Xi (x,z,\mathcal{E}) = \delta (x) \delta (z+p) \Xi (\mathcal{E}) [/tex]
for a a source at z = -p relative to a lens at z = 0.

3. The ABCD matrix of a the system is
[tex]M_{\mbox{system}} =
\begin{bmatrix}
1& q \\
0& 1 \end{bmatrix}
\begin{bmatrix}
1& 0 \\

-1/f & 1 \end{bmatrix}
\begin{bmatrix}
1& p \\

0& 1 \end{bmatrix} [/tex]
where
[tex]q = \frac{fp}{f+p}[/tex]
via the imaging equation
[tex] \frac{1}{p} + \frac{1}{q} = \frac{1}{f} [/tex]

The Attempt at a Solution



Let me go term by term:

As the problem says, scattering is ignored, so
[tex] \left[ Kw \right] _{\mbox{scattering}} = 0 [/tex]
Absorption should have the same generic form:
[tex] \left[ -\frac{c}{n} \mu w \right] _{\mbox{absorption}} [/tex]
Emission should have the form
[tex] \left[ \Xi _{p,\mathcal{E}} \right] _{\mbox{emission}} = \frac{1}{\mathcal{E}} \delta (x) \delta (z+p) \Xi (\mathcal{E})[/tex]
I'm not sure about propagation. Specifically how to relate the term
[tex] \left[ -\frac{c}{n} \, \hat{s} \cdot \nabla w \right] _{\mbox{propagation}}[/tex]
to the radiance L. I know the radiance is conserved and that I can write
[tex] L_{\mbox{out}} \left(
\begin{bmatrix}
\vec{r} \\
\hat{s}_{\perp} \end{bmatrix} \right) = L_{\mbox{in}} \left(
M_{\mbox{system}} \begin{bmatrix}
\vec{r} \\
\hat{s}_{\perp} \end{bmatrix} \right)= L_{\mbox{in}} \left(
\begin{bmatrix}
1& q \\

0& 1 \end{bmatrix}
\begin{bmatrix}
1& 0 \\

-1/f & 1 \end{bmatrix}
\begin{bmatrix}
1& p \\

0& 1 \end{bmatrix} \begin{bmatrix}
\vec{r} \\
\hat{s}_{\perp} \end{bmatrix} \right)[/tex]
So, can I write
[tex] \left[ -\frac{c}{n} \, \hat{s} \cdot \nabla w \right] _{\mbox{propagation}} = -\frac{c}{n} L_{\mbox{in}} \left(
M_{\mbox{system}} \begin{bmatrix}
\vec{r} \\
\hat{s}_{\perp} \end{bmatrix} \right)= -\frac{c}{n} L_{\mbox{in}} \left(
\begin{bmatrix}
1& q \\

0& 1 \end{bmatrix}
\begin{bmatrix}
1& 0 \\

-1/f & 1 \end{bmatrix}
\begin{bmatrix}
1& p \\

0& 1 \end{bmatrix} \begin{bmatrix}
\vec{r} \\
\hat{s}_{\perp} \end{bmatrix} \right)[/tex]
the above?

I would appreciate any comments or suggestions that can lead me to the answer or the answer, if you just happen to know. :smile:
 
Last edited:
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  • #2


Your approach seems correct. The propagation term can be related to the radiance by using the radiative transfer equation and the imaging equation. You can write it as:
\left[ -\frac{c}{n} \, \hat{s} \cdot \nabla w \right] _{\mbox{propagation}} = -\frac{c}{n}L_{\mbox{in}} \left(M_{\mbox{system}} \begin{bmatrix} \vec{r} \\ \hat{s}_{\perp} \end{bmatrix} \right) = -\frac{c}{n}\frac{1}{\mathcal{E}}\delta(x)\delta(z+p)\int L_{\mbox{in}} \left(M_{\mbox{system}} \begin{bmatrix} \vec{r} \\ \hat{s}_{\perp} \end{bmatrix} \right) d\mathcal{E}
Using the ABCD matrix and the imaging equation, you can simplify this to:
\left[ -\frac{c}{n} \, \hat{s} \cdot \nabla w \right] _{\mbox{propagation}} = -\frac{c}{n}\frac{1}{\mathcal{E}}\delta(x)\delta(z+p)L_{\mbox{in}} \left(M_{\mbox{system}} \begin{bmatrix} \vec{r} \\ \hat{s}_{\perp} \end{bmatrix} \right) = -\frac{c}{n}\frac{1}{\mathcal{E}}\delta(x)\delta(z+p)L_{\mbox{in}} \left(\begin{bmatrix} 1& q \\ 0& 1 \end{bmatrix} \begin{bmatrix} \vec{r} \\ \hat{s}_{\perp} \end{bmatrix} \right) = -\frac{c}{n}\frac{1}{\mathcal{E}}\delta(x)\delta(z+p)L_{\mbox{in}} \left(\begin{bmatrix} \vec{r} + q\hat{s} \\ \hat{s}_{\perp} \end{bmatrix} \right)
This can be further simplified using the imaging equation
 

1. What is the radiative transfer equation?

The radiative transfer equation is a mathematical equation used to describe the flow of electromagnetic radiation through a medium. It takes into account factors such as absorption, scattering, and emission of radiation by particles in the medium.

2. What is a point source in the context of the radiative transfer equation?

A point source is a theoretical concept in the radiative transfer equation that represents a single location from which radiation is emitted or scattered in all directions. It is often used to simplify calculations and understand the behavior of radiation in a medium.

3. How does a thin lens affect the radiative transfer equation?

A thin lens is a material with a thickness much smaller than the wavelength of the radiation passing through it. It can alter the direction and intensity of the radiation, and the radiative transfer equation takes into account these effects when a thin lens is present in the medium.

4. What are some applications of the radiative transfer equation?

The radiative transfer equation is used in fields such as atmospheric science, astrophysics, and remote sensing to understand the behavior of radiation in different environments. It is also used in engineering and design processes, such as in the development of optical systems and devices.

5. How is the radiative transfer equation solved?

The radiative transfer equation is a complex equation that can be solved using numerical methods and computer simulations. It requires knowledge of the properties of the medium and the radiation, as well as boundary conditions and assumptions about the behavior of the radiation. Approximations and simplifications may also be used to solve the equation in certain cases.

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