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nokia8650
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A railway truck S of mass 2000 kg is traveling due east along a straight horizontal track with constant speed 12 m s–1. The truck S collides with a truck T which is traveling due west along the same track as S with constant speed 6 m s–1. The magnitude of the impulse of T on S is 28 800 Ns.
Calculate the speed of S immediately after the collision
My calculation goes:
28800 = 2000(v-12)
However, the markscheme has it as 28800 = 2000(12-v)
Both of these clearly yield different solutions. Is it due to the fact that the impulse is in fact -28800 (minus 28800)? How would one know that though?
Thanks
Calculate the speed of S immediately after the collision
My calculation goes:
28800 = 2000(v-12)
However, the markscheme has it as 28800 = 2000(12-v)
Both of these clearly yield different solutions. Is it due to the fact that the impulse is in fact -28800 (minus 28800)? How would one know that though?
Thanks