Rate of Reaction: Calculating with Hydrogen Peroxide & Catalase

In summary: During the experiment, I tested different concentrations of hydrogen peroxide- 3%, 2.4%, 1.8%, 1.2% and 0.6%.The average rate of reaction was 2 mL of O2/sec.
  • #1
Flomer
3
0

Homework Statement


Hello all,

I'm currently in high school and I'm doing a biology experiment with catalase reacting with hydrogen peroxide. I have measured the total amount of gas produced in terms of mL during the reaction which took place over 30 seconds.

Throughout the experiment I'm testing different concentrations of hydrogen peroxide - 3%, 2.4%, 1.8%, 1.2% and 0.6%.

Homework Equations


If I would like to calculate the average rate of reaction do I simply divide the total amount of gas produced with time?

We were not allowed to use a pressure sensor by our teacher.

The Attempt at a Solution


For example:

Hydrogen Peroxide Concentration: 3%
Gas Produced: 60 mL of O2
Time: 30 sec
Rate of reaction: 2 mL O2/sec

Is this correct? Is the unit correct?

- Flomer
 
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  • #2
This is a correct average rate. Doesn't mean it was constant and identical all the time.

Besides, you can be required to give the answer in mol/sec. But what you wrote is perfectly acceptable.
 
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  • #3
Flomer said:

Homework Statement


Hello all,

I'm currently in high school and I'm doing a biology experiment with catalase reacting with hydrogen peroxide. I have measured the total amount of gas produced in terms of mL during the reaction which took place over 30 seconds.

Throughout the experiment I'm testing different concentrations of hydrogen peroxide - 3%, 2.4%, 1.8%, 1.2% and 0.6%.

Homework Equations


If I would like to calculate the average rate of reaction do I simply divide the total amount of gas produced with time?

We were not allowed to use a pressure sensor by our teacher.

The Attempt at a Solution


For example:

Hydrogen Peroxide Concentration: 3%
Gas Produced: 60 mL of O2
Time: 30 sec
Rate of reaction: 2 mL O2/sec

Is this correct? Is the unit correct?

- Flomer

Your calculation is correct. Data is often written up preliminarily in the laboratory in the way you have.

Then in formal presentations in e.g. published scientific papers you'd probably recalculate in terms of more standard units such as moles O2 produced per litre reaction solution per sec. (you have not told us the volume you did the reaction in). But if you don't yet know what moles are or how to calculate them I wouldn't regard this as essential.

Reactions do not necessarily continue at the same rate so measuring amount of product after one fixed time is a somewhat unreliable measurement of rate if the rate slows a lot during the time of the measured reaction - if possible measure the same thing at say 30, 60 and 90 sec. I am curious how you started reaction, measured and timed, I mean it takes a few sec to mix - did you measure a difference in volumes over 30 sec?

We will be interested to see your results when you are ready.

Edit: I hadn't seen Borek's reply but I see we both say the same things!
 
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  • #4
Borek said:
This is a correct average rate. Doesn't mean it was constant and identical all the time.

Besides, you can be required to give the answer in mol/sec. But what you wrote is perfectly acceptable.

epenguin said:
Your calculation is correct. Data is often written up preliminarily in the laboratory in the way you have.

Then in formal presentations in e.g. published scientific papers you'd probably recalculate in terms of more standard units such as moles O2 produced per litre reaction solution per sec. (you have not told us the volume you did the reaction in). But if you don't yet know what moles are or how to calculate them I wouldn't regard this as essential.

Reactions do not necessarily continue at the same rate so measuring amount of product after one fixed time is a somewhat unreliable measurement of rate if the rate slows a lot during the time of the measured reaction - if possible measure the same thing at say 30, 60 and 90 sec. I am curious how you started reaction, measured and timed, I mean it takes a few sec to mix - did you measure a difference in volumes over 30 sec?

We will be interested to see your results when you are ready.

Edit: I hadn't seen Borek's reply but I see we both say the same things!

Thanks for the replies! We have not learned about mol yet and I don't think it is included in the standard level syllabus.

I understand that my calculation will only be the average rate and as you guys mentioned, it does not indicate how the rate of reaction changed over the 30 seconds. Should I mention this in my conclusion/evaluation?

The experiment is for my biology class and our teacher said that time had to be one of the control variables. But I do understand your point, Epenguin!

The volume for the reaction was 50 ml.

The experiment was carried out the following way:

  • A water bath was filled with water.
  • A graduated cylinder, filled with water, was inverted and placed in the bath. (So the water stayed in the upside-down cylinder)
  • I then added hydrogen peroxide into an Erlenmeyer Flask.
  • I then added the catalase.
  • The flask was stirred and the reaction was allowed to start for 10 sec.
  • A gas delivery tube was then connected between the flask and cylinder.
  • The reaction was allowed to take place over 30 sec (measured with a stop watch from the point when the delivery tube was connected).
  • After 30 seconds the delivery tube was disconnected and then I measured how much water "had left" the cylinder as the oxygen entered.

I had to go about it this way since we were not allowed to use a pressure sensor and instead we had to measure the total gas produced. Lastly, this method was the only one possible due to the materials my school offers. I know there are several improvements that can be made to this method and that there are unreliable parts of it - I'm planning to include this in my evaluation.

I hope this make sense. English is not my mother-tongue so if I need to clarify anything please tell me!
 
  • #5
OK, school experiments often have limitations.
Since, if I understand, you measured volume of oxygen by looking at the meniscus, it would have been little extra trouble to take different time measurements. But you may have some impression from the way it was bubbling if the reaction seemed to be continuing about the same at the end?

Delay between mixing and start of measurement, which there usually is, doesn't matter if reaction rate is constant. Don't worry about the moles, it is still an experiment which can give a conclusion.

Anyway what did the results look like, how did it depend on peroxide %?
 
  • #6
epenguin said:
OK, school experiments often have limitations.
Since, if I understand, you measured volume of oxygen by looking at the meniscus, it would have been little extra trouble to take different time measurements. But you may have some impression from the way it was bubbling if the reaction seemed to be continuing about the same at the end?

Delay between mixing and start of measurement, which there usually is, doesn't matter if reaction rate is constant. Don't worry about the moles, it is still an experiment which can give a conclusion.

Anyway what did the results look like, how did it depend on peroxide %?

I noticed especially with the trails using some of the lower concentrations there were fewer and fewer bubbles towards the end of the 30 seconds.

I have still to calculate most of the data - but the general trend is that the gas produced (rate of reaction) decreases as concentrations of peroxide decreases.

For example two of my results were the following:
3% peroxide - 60 mL gas
0.6% peroxide - 20 mL gas
 

1. What is the rate of reaction?

The rate of reaction refers to how quickly a chemical reaction occurs. It is usually measured in terms of the change in concentration of reactants or products over time.

2. How is the rate of reaction affected by hydrogen peroxide?

Hydrogen peroxide can act as a reactant or a product in a chemical reaction. Its concentration can affect the rate of reaction as it can increase or decrease the formation of products. In some cases, hydrogen peroxide can also act as a catalyst, speeding up the reaction without being consumed in the process.

3. What is catalase and how does it impact the rate of reaction?

Catalase is an enzyme found in living organisms that catalyzes the decomposition of hydrogen peroxide into water and oxygen. It speeds up the reaction by lowering the activation energy required for the reaction to occur. This allows the reaction to occur at a faster rate.

4. How is the rate of reaction calculated?

The rate of reaction is calculated by dividing the change in concentration of reactants or products by the change in time. This can be represented by the equation: Rate = (ΔC/Δt), where ΔC is the change in concentration and Δt is the change in time.

5. What are some factors that can affect the rate of reaction in this experiment?

Some factors that can affect the rate of reaction in this experiment include the concentration of hydrogen peroxide, the amount of catalase present, the temperature, and the pH level. Other factors such as the presence of inhibitors or the surface area of the reactants may also impact the rate of reaction.

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