Ratio problem: The ratio of Liquid X to Liquid Y in a mixture is 3 to 7

[JohnDoe01]

The ratio of Liquid X to Liquid Y in a mixture is 3 to 7. If the amount of Liquid Y in a mixture is 161, then the amount of Liquid x in the mixture is equal to?

 

[Greg]

Let $m$ be the total amount in the mixture. Then,

$$Y=\frac{7m}{10}=161$$

From that, can you find the amount for $X$, i.e. $\frac{3}{10}$ of the mixture?

 

[HallsofIvy]

Personally I wouldn't worry about the total amount at all. You are told that "ratio of Liquid X to Liquid Y in a mixture is 3 to 7" so \(\displaystyle \frac{X}{Y}= \frac{3}{7}\). You are told that "the amount of Liquid Y in a mixture is 161" so \(\displaystyle \frac{X}{161}= \frac{3}{7}\). \(\displaystyle X= \frac{3}{7}(161)\).