- #1
bornofflame
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Homework Statement
1. A 2.01 uFcapacitor that is initially uncharged is connected in series with a 6.51 kΩ resistor and an emf source with 74.6 V and negligible internal resistance. The circuit is completed at t = 0.
a) Just after the circuit is completed, what is the rate at which electrical energy is being dissipated in the resistor?
Given/Known:
##C = 2.01\cdot10^{-6} ~F##
##Q_0 = 0 ~C##
##R_1 = 6.51\cdot10^3 ~\Omega##
##\mathcal {E} = 74.6 ~V## (The source can be treated as ideal.)
Homework Equations
## P = \frac {V^2_{ab}} {R_{eq}}##
The Attempt at a Solution
I believe that the question is simply asking for the power across the resistor which is why that is the only equation that I have included. That said:
## P = \frac {V^2_{ab}} {R_{eq}} = \frac {74.6~V} {6.51\cdot10^3 ~\Omega}##
##=\frac {5565~V^2} {6.51\cdot10^3 ~\frac V A} = 854\cdot10^{-3} \frac V A = 854 \frac {mJ} {s}##
is my solution.
It seems pretty simple but I'm not as confident in my knowledge of circuits as I would like to be so I want to make sure that I'm understanding this before I move on to the next step.