Reaction energy for polymerization of polychloroprene

In summary, the concept of bond energies is essential in understanding the stability of molecules, and by using the table of bond energies, we can accurately calculate the energy released from breaking and forming bonds. Your calculations and setup for both parts b and c are correct, but it is important to note the importance of using the correct units and following the correct mathematical operations in scientific calculations.
  • #1
d.arbitman
101
4

Homework Statement


Please see attached for problem statement and table of bond energies. My chemistry background is awful and this is from a materials science textbook. The question is, how would I approach/solve 2.31 (only parts b and c).

Homework Equations



The Attempt at a Solution


We go from two double bonds (C= C) and a single bond (C - C) to two single bonds (C-C) and one double bond (C= C)
(2*3.7E5 + 6.8E5) - (2*6.8E5) = 60 kJ/mole

The molecular mass of the 'mer' is 88.53 g/mole.
1kg/88.53g = 11.30 moles
60 kJ/mole * 11.30 mole = 678 kJ

I know both of these are the correct answer, but I just need verification of my problem setup.

Thanks.
 

Attachments

  • Image011220141350051.jpg
    Image011220141350051.jpg
    28 KB · Views: 1,258
  • Image011220141422491.jpg
    Image011220141422491.jpg
    24 KB · Views: 1,064
Physics news on Phys.org
  • #2


I would approach this problem by first understanding the concept of bond energies and how they relate to the stability of molecules. In this case, we are dealing with the conversion of double bonds to single bonds, which will result in a more stable molecule.

To solve part b, we need to calculate the energy released from breaking the two double bonds and forming two single bonds. Using the table of bond energies, we can see that the energy required to break a double bond is 6.8E5 kJ/mole, and the energy released from forming a single bond is 3.7E5 kJ/mole. So for two double bonds, we have (2*6.8E5) - (2*3.7E5) = 6.8E5 kJ/mole.

To solve part c, we need to calculate the total energy released from breaking the two double bonds and forming one double bond. Using the same concept as part b, we can see that the energy required to break two double bonds is (2*6.8E5) = 13.6E5 kJ/mole, and the energy released from forming one double bond is (1*6.8E5) = 6.8E5 kJ/mole. So the total energy released is 13.6E5 - 6.8E5 = 6.8E5 kJ/mole.

Your calculations and setup for both parts b and c are correct. However, as a scientist, it is important to always double-check our work and make sure we are using the correct units and following the correct mathematical operations. In this case, the units for bond energies are kJ/mole, so we should not convert to moles before calculating the energy released. So for part c, the correct calculation would be (2*6.8E5) - (1*6.8E5) = 6.8E5 kJ/mole.

Overall, your approach and solution to this problem are valid, but as a scientist, it is important to always double-check our work and make sure we are using the correct units and following the correct mathematical operations.
 

1. What is reaction energy for polymerization of polychloroprene?

Reaction energy for polymerization of polychloroprene is the amount of energy released or absorbed during the process of joining monomer units to form a polymer chain. In this case, it refers to the energy involved in the formation of polychloroprene from chloroprene monomers.

2. How is reaction energy for polymerization of polychloroprene measured?

Reaction energy for polymerization of polychloroprene is typically measured using calorimetry, which involves measuring the heat released or absorbed during the reaction. This can be done using a bomb calorimeter or a differential scanning calorimeter.

3. What factors affect the reaction energy for polymerization of polychloroprene?

The reaction energy for polymerization of polychloroprene can be influenced by a variety of factors, including temperature, concentration of monomers, presence of catalysts, and molecular weight of the resulting polymer. Other factors, such as solvent choice and polymerization method, can also impact the reaction energy.

4. Why is the reaction energy for polymerization of polychloroprene important?

The reaction energy for polymerization of polychloroprene is important because it can affect the properties of the resulting polymer. Higher reaction energy can lead to a stronger and more durable polymer, while lower reaction energy can result in a weaker and less stable polymer. Understanding the reaction energy can also help in optimizing the polymerization process.

5. How does the reaction energy for polymerization of polychloroprene compare to other polymers?

The reaction energy for polymerization of polychloroprene can vary depending on the specific conditions and methods used. However, it generally falls within the range of other similar polymers, such as polyethylene and polystyrene. The reaction energy can also be affected by the specific monomer structure and the type of polymerization mechanism involved.

Similar threads

  • Biology and Chemistry Homework Help
Replies
6
Views
2K
  • Biology and Chemistry Homework Help
Replies
2
Views
5K
  • Biology and Chemistry Homework Help
Replies
1
Views
1K
  • Biology and Chemistry Homework Help
Replies
5
Views
2K
  • Biology and Chemistry Homework Help
Replies
4
Views
1K
  • Biology and Chemistry Homework Help
Replies
3
Views
2K
  • Biology and Chemistry Homework Help
Replies
3
Views
2K
  • Biology and Chemistry Homework Help
Replies
1
Views
6K
  • Biology and Chemistry Homework Help
Replies
3
Views
5K
  • Biology and Chemistry Homework Help
Replies
19
Views
3K
Back
Top