Thanks. Unfortunately, the particular modulus was not specified.jrmichler said:The thermal coefficient of expansion is one property. It describes how much an unconstrained object changes size with temperature change.
The modulus of elasticity, AKA elastic modulus, AKA Young's modulus, describes how much an object changes size with stress change.
You need to use the correct terms to avoid confusion.
If a polymer is constrained inside a rigid cylinder, then there is no thermal expansion. That is a simple problem to solve. Step 1: Calculate thermal expansion from temperature change. Step 2: Calculate stress to force the part back to its original size. Step 3 (optional): Calculate the force to get that stress.
One good way to get a better understanding of the relationships is to do the calculations for one polymer, then repeat for a different polymer with different properties.
Thanks. Unfortunately the particular modulus is not specified but probably Youngs.jrmichler said:The thermal coefficient of expansion is one property. It describes how much an unconstrained object changes size with temperature change.
The modulus of elasticity, AKA elastic modulus, AKA Young's modulus, describes how much an object changes size with stress change.
You need to use the correct terms to avoid confusion.
If a polymer is constrained inside a rigid cylinder, then there is no thermal expansion. That is a simple problem to solve. Step 1: Calculate thermal expansion from temperature change. Step 2: Calculate stress to force the part back to its original size. Step 3 (optional): Calculate the force to get that stress.
One good way to get a better understanding of the relationships is to do the calculations for one polymer, then repeat for a different polymer with different properties.
Thank youFEAnalyst said:You didn’t say which modulus you mean but I’ll also assume that it’s just Young’s modulus and share simple formulas involving thermal expansion coefficient and aforementioned modulus of elasticity: $$\Delta L= \alpha L_{0} \Delta T$$ $$\varepsilon=\frac{\Delta L}{L_{0}}$$ $$E=\frac{\sigma}{\varepsilon}$$ $$\sigma=E \varepsilon=E \alpha \Delta T$$
The relationship between modulus and thermal expansion is that as the temperature of a material increases, its modulus (or stiffness) decreases, causing it to expand. This is due to the increased vibration of molecules at higher temperatures, which creates more space between them and causes the material to expand.
Thermal expansion causes the modulus of a material to decrease, making it less stiff. This is because as the material expands, the distance between molecules increases, making it easier for them to move and reducing the overall stiffness of the material.
Yes, thermal expansion can cause a material to become weaker. As the material expands, the distance between molecules increases, making it easier for them to move and reducing the overall stiffness of the material. This can lead to a decrease in the material's strength and potentially cause it to fail.
The modulus of a material has an inverse relationship with its thermal expansion. This means that as the modulus of a material increases, its thermal expansion decreases. This is because a higher modulus indicates a stiffer material, which is less affected by changes in temperature.
Yes, the relationship between modulus and thermal expansion can be used to predict a material's behavior. By understanding how a material's modulus changes with temperature, we can anticipate how it will expand or contract and how it will respond to changes in its environment. This information is important for designing and engineering materials for specific applications.