- #1
resurgance2001
- 197
- 9
A student I am working with showed me a problem they have been working on.
In the first part of the question there are two loudspeaker facing each other. The student has been told that they can treat this situation as an closed tube. The frequency of the note is such that its wavelength is equal to the distance between the loudspeakers.
In this situation we determined that there are nodes at the speakers and another node midway between the speakers. The amplitude of the anti-nodes found 1/4 and 3/4 of the distance from one speaker would be twice the amplitude from one speacker. Would one accept that this is correct? At least if one is told to assume that the situation works as a closed tube. (I am not 100% convinced of this)
If one assumes that we asnwered correctly in the situation above, what would be the effect of reversing the polarity of the wires in one loudspeaker? We answered that this would make the 2 speakers exactly 180 degrees out of phase which would result in a diminishing of the volume at all places. Is that correct?
thanks
Peter
In the first part of the question there are two loudspeaker facing each other. The student has been told that they can treat this situation as an closed tube. The frequency of the note is such that its wavelength is equal to the distance between the loudspeakers.
In this situation we determined that there are nodes at the speakers and another node midway between the speakers. The amplitude of the anti-nodes found 1/4 and 3/4 of the distance from one speaker would be twice the amplitude from one speacker. Would one accept that this is correct? At least if one is told to assume that the situation works as a closed tube. (I am not 100% convinced of this)
If one assumes that we asnwered correctly in the situation above, what would be the effect of reversing the polarity of the wires in one loudspeaker? We answered that this would make the 2 speakers exactly 180 degrees out of phase which would result in a diminishing of the volume at all places. Is that correct?
thanks
Peter