shouldn't the angular velocity be pi/6?Daeho Ro said:When it moves with maximum speed, the angular velocity is ## \omega_i = \pi / 12. ## You want to stop it within ## 3.5 ## revolution, that is ## \theta_f - \theta_i = 7\pi ## and it have to be ## \omega_f = 0. ## Then, you can get the angular acceleration, ## \alpha. ##
Can you also help me check this one? You hold a small ice cube near the top edge of a hemispherical bowl of radius 100 mm. You release the cube from rest. What is the magnitude of its acceleration at the instant it reaches the bottom of the bowl? Ignore friction. is a=2g=19.6 m/s2Daeho Ro said:Oh, yes I missed the factor ## 2##.
Which one?kolua said:or -pi2/504 s-2
Rotational acceleration refers to the rate of change of angular velocity, which is the speed at which an object rotates around an axis. It is measured in radians per second squared (rad/s²) or degrees per second squared (deg/s²).
Rotational acceleration is calculated by dividing the change in angular velocity by the change in time. It can also be calculated by taking the second derivative of the rotational displacement with respect to time.
The factors that affect rotational acceleration include the moment of inertia, the torque applied to the object, and the distance from the axis of rotation to the point where the force is applied. Other factors may include the shape and mass distribution of the object, as well as any external forces acting on it.
Rotational acceleration refers to the acceleration of an object as it rotates around an axis, while linear acceleration refers to the acceleration of an object as it moves in a straight line. Rotational acceleration is measured in units of angular velocity, while linear acceleration is measured in units of velocity.
Real-life examples of rotational acceleration include the motion of a spinning top, the rotation of a carousel, or the movement of a Ferris wheel. Other examples may include the rotation of Earth on its axis, the spinning of a figure skater, or the rotation of a car tire.