- #1
daudaudaudau
- 302
- 0
Hi. I'm reading an article which writes the following
"... and the well-known expression for the charge current is"
[tex]
j=-\frac{ie}{m}\int dr\psi^\dagger (r)[\nabla-ieA(r)]\psi(r)
[/tex]
Why does it have an integral sign? And when you define it this way, you integrate out the r-dependence, don't you?
"... and the well-known expression for the charge current is"
[tex]
j=-\frac{ie}{m}\int dr\psi^\dagger (r)[\nabla-ieA(r)]\psi(r)
[/tex]
Why does it have an integral sign? And when you define it this way, you integrate out the r-dependence, don't you?